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Alla [95]
3 years ago
5

What is the ph of a solution of 0.400 m k2hpo4, potassium hydrogen phosphate?

Chemistry
1 answer:
dusya [7]3 years ago
3 0
When we can get Pka for K2HPO4 =6.86 so we can determine the Ka :

when Pka = - ㏒ Ka

          6.86 = -㏒ Ka 

∴Ka = 1.38 x 10^-7

by using ICE table:

               H2PO4- →  H+  + HPO4
initial      0.4 m            0         0

change     -X                +X       +X

Equ       (0.4-X)               X          X

when Ka = [H+][HPO4] / [H2PO4-]

by substitution:

1.38 X 10^-7 = X^2 / (0.4-X)   by solving for X

∴X = 2.3x 10^-4 

∴[H+] = X = 2.3 x 10^-4

∴PH = -㏒[H+]

        = -㏒ (2.3 x 10^-4)
 ∴PH  =  3.6

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A container has the dimensions of 10cm x 80mm x 0.15m. The density of
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Answer:

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6 0
3 years ago
List the number of each type of atom on the right side of the equation hbr(aq)+2naoh(aq)→2nabr(s)+h2o(l)
ser-zykov [4K]

On the basis of the given unbalanced equation, that is:

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