Answer:
Particle Symbol Mass
electron e- 0.0005486 amu
proton p+ 1.007276 amu
neutron no 1.008665
Answer:
186 Liters at STP conditions
Explanation:
1 mole of any gas at STP conditions occupies 22.4 Liters.
Therefore, 8.32 moles O₂(g) = 8.32 moles x 22.4Liters/mole = 186 Liters (3 sig.figs.)
Answer:
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Answer:
11.4 moles
Explanation:
Your chemical equation for the reaction of zinc and nitric acid will be
Zn + 4 HNO₃ --> Zn(NO₃)₂ + 2 NO₂ + 2 H₂O
To solve the problem, you need to use stoichiometry. For every 1 mole of zinc, you will need 4 moles of nitric acid. Divide 45.60 by 4. Your answer should be 11.4 moles.
