Given:
Assuming the transition to turbulence for flow over a flat plate happens at a Reynolds number of 5x105, determine the following for air at 300 K and engine oil at 380 K. Assume the free stream velocity is 3 m/s.
To Find:
a. The distance from the leading edge at which the transition will occur.
b. Expressions for the momentum and thermal boundary layer thicknesses as a function of x for a laminar boundary layer
c. Which fluid has a higher heat transfer
Calculation:
The transition from the lamina to turbulent begins when the critical Reynolds
number reaches 



Answer:
q = 1.73 W
Explanation:
given data
small end = 5 cm
large end = 10 cm
high = 15 cm
small end is held = 600 K
large end at = 300 K
thermal conductivity of asbestos = 0.173 W/mK
solution
first we will get here side of cross section that is express as
...............1
here x is distance from small end and S1 is side of square at small end
and S2 is side of square of large end and L is length
put here value and we get
S = 5 +
S =
m
and
now we get here Area of section at distance x is
area A = S² ...............2
area A =
m²
and
now we take here small length dx and temperature difference is dt
so as per fourier law
heat conduction is express as
heat conduction q =
...............3
put here value and we get
heat conduction q =
it will be express as
now we intergrate it with limit 0 to 0.15 and take temp 600 to 300 K
solve it and we get
q (30) = (0.173) × (600 - 300)
q = 1.73 W
Answer: The feed rate is
17,020kg/he and the rate is 13,520kg/h
Check the attachment for step by step explanation
Answer:
Explanation along with code and output results is provided below.
C++ Code:
#include <iostream>
using namespace std;
int main()
{
int year;
cout<<"Enter the car model year."<<endl;
cin>>year;
if (year<=1969)
{
cout<<"Few safety features."<<endl;
}
else if (year>=1970 && year<1989)
{
cout<<"Probably has seat belts."<<endl;
}
else if (year>=1990 && year<1999)
{
cout<<"Probably has antilock brakes."<<endl;
}
else if (year>=2000)
{
cout<<"Probably has airbags."<<endl;
}
return 0;
}
Explanation:
The problem was to print feature messages of a car given its model year.
If else conditions are being used incorporate the logic. The code has been tested with several inputs and got correct output results.
Output:
Enter the car model year.
1961
Few safety features.
Enter the car model year.
1975
Probably has seat belts.
Enter the car model year.
1994
Probably has antilock brakes.
Enter the car model year.
2005
Probably has airbags.