The gravitational force between two objects is represented by the variable F. If the distance is decreased by 5 what is the new
1 answer:
The universal law of gravitation states that:
Every object in the universe attracts every other object with a force which is proportional to the product of their masses and inversely proportional to the square of distance between them.
It means that if the gravitational force is F, then if the distance is decreased by 5 times, then the new gravitation force is:
F/5² = F/25
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Considering the Ohm's law, the resistance of the lightbulb is 144.58 Ω.
<h3>Definition of current</h3>The flow of electricity through an object, such as a wire, is known as current (I). Its unit of measure is amps (A). So the current is a measure of the speed at which the charge passes a given reference point in a specified direction.
<h3>Definition of voltage</h3>The driving force (electrical pressure) behind the flow of a current is known as voltage and is measured in volts (V) (voltage can also be referred to as the potential difference or electromotive force). That is, voltage is a measure of the work required to move a charge from one point to another.
<h3>Definition of resistance</h3>Resistance (R) is the difficulty that a circuit opposes to the flow of a current and it is measured in ohms (Ω).
<h3>Ohm's law</h3>Ohm's law establishes the relationship between current, voltage, and resistance in an electrical circuit.
This law establishes that the intensity of the current that passes through a circuit is directly proportional to the voltage of the same and inversely proportional to the resistance that it presents.
Mathematically, Ohm's law is expressed as:
Where:
- I is the current measured in amps (A).
- V the voltage measured in volts (V).
- R the resistance that is measured in ohms (Ω).
In this case, you know that the voltage between two points in a circuit is 120 V and there is a current of 0.83 A.
Replacing in the Ohm's Law:
Solving:
0.83 A× R= 120 V
<u><em>R= 144.58 Ω</em></u>
Finally, the resistance of the lightbulb is 144.58 Ω.
Learn more about Ohm's law:
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