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uysha [10]
3 years ago
9

Definition plz someone plz plz plz

Chemistry
1 answer:
lubasha [3.4K]3 years ago
5 0
Force: any interaction that, when unopposed, will change the motion of an object.

Mass: the quantity of matter in a body regardless of its volume or of any forces acting on it

Acceleration: rate of change of velocity of an object with respect to time
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What is the difference between acute and chronic radiation poisoning
tatiyna
Acute radiation can be healed by developing cells (white blood cells) in the body. During Chronic radiation immense amount of energy is released into your body causing division and break down of cells which can cause cancer and internal bleeding and cannot be cured depending on the amount released.
6 0
3 years ago
How would local residents of a place be affected by changes in the hydrosphere? (please help!!)
lesya692 [45]

Answer:

Humans have impacted the hydrosphere drastically and will only continue to due so based on population needs. Global climate change, water pollution, damming of rivers, wetland drainage, reduction in stream flow, and irrigation have all exerted pressure on the hydrosphere's existing freshwater systems.

Hope it helps :)

6 0
3 years ago
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If antique brass is 30.0% zinc and 70.0% copper, how many grams of antique brass can be made from 18.0 grams of zinc and 32.8 gr
wariber [46]

Answer: 51.86

Explanation:

3 0
3 years ago
At sea level, where the pressure was 104 kPa and temperature 21.1 ºC, a certain mass of air occupies 2.0 m3 . To what volume wil
Romashka [77]

Answer:

The volume of air at where the pressure and temperature are  52 kPa, -5.0 ºC is 3.64 m^3.

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 104 kPa

P_2 = final pressure of gas = 52 kPa

V_1 = initial volume of gas = 2.0m^3

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 21.1^oC=273+21.1=294.1K

T_2 = final temperature of gas = -5.0^oC=273+(-5.0)=268 K

Now put all the given values in the above equation, we get:

\frac{104 kPa\times 2.0m^3}{294.1 K}=\frac{52 kPa\times V_2}{268 K}

V_2=3.64 m^3

The volume of air at where the pressure and temperature are  52 kPa, -5.0 ºC is 3.64 m^3.

3 0
3 years ago
If a ballon at 3.4 atm at 301k, what is the pressure when cooled to 212k
stepladder [879]

Answer:

2.39 atm

Explanation:

- Use Gay-Lussac's law

- P2 = P1T2/T1

- Fill in with our values

- Hope this helped! Please let me know if you need further explanation.

8 0
3 years ago
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