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ExtremeBDS [4]
3 years ago
14

Write a use of reverberation

Physics
1 answer:
MakcuM [25]3 years ago
3 0

Hello there!

<u>definition of reverberation:</u> "Prolongation of a sound; resonance."

<u>reverberation in a sentence:</u> The school's special effects team added reverberation to the actress's monologue to make her speech more dramatic and the school play a little more interesting.

I hope this helps, have a great day! ^-^


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What do work and energy have in common
spayn [35]

Energy and Work have the same unit of measurement which is Joules in SI units.

Explanation:

  • A Joule of Work is said to be done on an object when energy is transferred to that particular object.
  • If two objects are involved, when one object transfers energy onto the second, a joule of work is said to be done by the first object.  
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  • Kinetic energy is defined as the energy of a moving object while potential energy is known as the energy that is stored within an object.
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  • Both energy and work are measured in Joules.
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3 years ago
It is now 9:11 a.m. but when the bell rings at 9:12 a.m. Susie will be late for Mrs. Garner's U.S. History class for the 3rd tim
GaryK [48]

Answer:

3.1 m/s

Explanation:

The total distance she has to run is the addition of the three lengths:

47 + 63 + 76 = 186 meters.

She needs to cover it one minute (60 seconds). Therefore her speed must be:

186 m / 60 s = 3.1 m/s

6 0
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A rocket burns fuel as it shoots into the sky. What happens to the mass and volume of the rocket?
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6 0
3 years ago
A student drops two metallic objects into a 120-g steel container holding 150 g of water at 25°C. One object is a 206-g cube of
spayn [35]

Answer:

Mass of the aluminium chunk = 278.51 g

Explanation:

For an isolated system as given the energy lost and gains in the system will be zero therefore sum of all transfer of energy will be zero,as the temperature will also remain same

A specific heat formula is given as                  

Energy Change = Mass of liquid x Specific Heat Capacity x Change in temperature

                                       Q =  m×c×ΔT

                        Heat gain by aluminium + heat lost by copper  = 0    (1)

For Aluminium:

      Q = m\times0.897\frac{J}{g.k}\times(25-5)

      Q = m x 17.94 joule

For Copper:

Q= 206g\times0.385\frac{J}{g.k} \times(88-25)

       Q= 4996.53 Joule

from eq 1

     m x 17.94 = 4996.53

     mass of aluminium = \frac{4996.53}{17.94} g

    Mass of the aluminium chunk = 278.51 g

                         

3 0
3 years ago
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