Consider the process of diluting 1.2 M NH4Cl solution to prepare 1.4 L of a 0.25 M NH4Cl solution. Determine if each of the foll
1 answer:
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Answer:
1.4952 grams of sodium bicarbonate she would need to ingest to neutralize this much HCl.
Explanation:
Moles of hydrochloric acid = n
Volume of hydrochloric acid solution = 200.0 mL = 0.200 L
Molarity of the hydrochloric acid = 0.089 M
of HCL
According to reaction, 1 mole of HCl is neutralized by 1 mole of sodium bicarbonate.
Then 0.0178 moles of HCl wil be neutralized by :
of sodium bicarbonate
Mass of 0.0178 moles of sodium bicarbonate:
0.0178 mol × 72 g/mol = 1.4952 g
1.4952 grams of sodium bicarbonate she would need to ingest to neutralize this much HCl.
Answer:
PI = 6.04
In the attached figure are the missing hydrogen atoms
Explanation:
Given both pk, the isoelectric point will be equal to:
PI = (1/2)*(pka + pka2), where pka = 2.32 and pka2 = 9.76
PI = (1/2)*(2.32 + 9.76) = 6.04
