Consider the process of diluting 1.2 M NH4Cl solution to prepare 1.4 L of a 0.25 M NH4Cl solution. Determine if each of the foll
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Answer : The mass of calcium phosphate and the mass of sodium chloride that formed could be, 9.3 and 10.5 grams respectively.
Explanation : Given,
Mass of = 12.00 g
Mass of = 10.0 g
Molar mass of = 164 g/mol
Molar mass of = 111 g/mol
Molar mass of = 58.5 g/mol
Molar mass of = 310 g/mol
First we have to calculate the moles of and
.
and,
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is:
From the balanced reaction we conclude that
As, 3 mole of react with 2 mole of
So, 0.0901 moles of react with
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of and
From the reaction, we conclude that
As, 3 mole of react to give 6 mole of
So, 0.0901 mole of react to give
mole of
and,
As, 3 mole of react to give 1 mole of
So, 0.0901 mole of react to give
mole of
Now we have to calculate the mass of and
and,
Therefore, the mass of calcium phosphate and the mass of sodium chloride that formed could be, 9.3 and 10.5 grams respectively.