Answer:
i = 2.483
Explanation:
The vapour pressure lowering formula is:
Pₐ = Xₐ×P⁰ₐ <em>(1)</em>
For electrolytes:
Pₐ = nH₂O / (nH₂O + inMgCl₂)×P⁰ₐ
Where:
Pₐ is vapor pressure of solution (<em>0.3624atm</em>), nH₂O are moles of water, nMgCl₂ are moles of MgCl₂, i is Van't Hoff Factor, Xₐ is mole fraction of solvent and P⁰ₐ is pressure of pure solvent (<em>0.3804atm</em>)
4.5701g of MgCl₂ are:
4.5701g ₓ (1mol / 95.211g) = 0.048000 moles
43.238g of water are:
43.238g ₓ (1mol / 18.015g) = 2.400 moles
Replacing in (1):
0.3624atm = 2,4mol / (2.4mol + i*0.048mol)×0.3804atm
0.3624atm / 0.3804atm = 2,4mol / (2.4mol + i*0.048mol)
2.4mol + i*0.048mol = 2.4mol / 0.9527
2.4mol + i*0.048mol = 2.5192mol
i*0.048mol = 2.5192mol - 2.4mol
i = 0.1192mol / 0.048mol
<em>i = 2.483</em>
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I hope it helps!
Answer:
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Explanation:
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Give the positional isomers of 2 halopropane
(CH3)2CH
answer:
is in file download it
Addition of chlorine to water gives both hydrochloric acid (HCl) and hypochlorous acid (HClO)
What are Transition metal oxides ?
Transition metal oxides (TMOs) are another class of nanomaterials, frequently used as anode in alkaline batteries due to their distinctive properties such as abundant active sites, short diffusion pathways, low preparation cost, high theoretical capacity and distinct reaction mechanism.
Cl2 + H2O ⇌ HClO + HCl
Cl2 + 4 OH− ⇌ 2 ClO− + 2 H2O + 2 e−
Cl2 + 2 e− ⇌ 2 Cl−
The acid can also be prepared by dissolving dichlorine monoxide in water; under standard aqueous conditions, anhydrous hypochlorous acid is currently impossible to prepare due to the readily reversible equilibrium between it and its anhydride.
2 HClO ⇌ Cl2O + H2O K (at 0 °C) = 3.55×10−3 dm3 mol−1
The presence of light or transition metal oxides of copper, nickel, or cobalt accelerates the exothermic decomposition into hydrochloric acid and oxygen
2 Cl2 + 2 H2O → 4 HCl + O2
To learn more about exothermic decomposition click on the link below:
brainly.com/question/20089404
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