Answer:
Measuring with a ruler and using final volume minus initial volume
Explanation:
You can measure the volume of a geometric object by measuring its sides with a ruler and calculating the volume according to the corresponding formula for each object. For example, for a rectangular prism it would be
You can also measure the volume of an object by measuring how much water it displaces. To do this you have to fill a measuring cylinder with enough water for the object to be completely submerged and take note of the volume. Then, add the object and note again the volume of the water+object. The difference between both is the volume of the object.
The advantage of the second method is that it can be used for objects with irregular shapes as long as they do not float.
Answer:
Dichloromethane
Explanation:
As we know the atomic number given belongs to following elements, i.e.
Atomic # Element M.Mass
1 Hydrogen 1 g.mol⁻¹
6 Carbon 12 g.mol⁻¹
17 Chlorine 35.5 g.mol⁻¹
Also the molecular formula of Dichloromethane is,
= CH₂Cl₂
Putting molar masses of each element,
= (12)₁ + (1)₂ + (35.5)₂
= 12 + 2 + 71
= 85 g.mol⁺¹
Result:
Hence the only possible structure containing 5 atoms is Dichloromethane.
The correct answer is c because enzymes increase the rate of all biochemical processes
Answer:
Option D. KBr < KCl < NaCl
Explanation:
We'll begin by calculating the number of mole of each sample.
This can be obtained as follow:
For NaCl:
Mass = 1 g
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Mole of NaCl =?
Mole = mass /Molar mass
Mole of NaCl = 1/58.5
Mole of NaCl = 0.0171 mole
For Kbr:
Mass = 1 g
Molar mass of KBr = 39 + 80 = 119 g/mol
Mole of KBr =?
Mole = mass /Molar mass
Mole of KBr = 1/119
Mole of KBr = 0.0084 mole
For KCl:
Mass = 1 g
Molar mass of KCl = 39 + 35.5 = 74.5 g/mol
Mole of KCl =?
Mole = mass /Molar mass
Mole of KCl = 1/74.5
Mole of KCl = 0.0134 mole
Summary
Sample >>>>>>>> Number of mole
NaCl >>>>>>>>>> 0.0171
KBr >>>>>>>>>>> 0.0084
KCl >>>>>>>>>>> 0.0134
Arranging the number of mole of the sampl in increasing order, we have:
KBr < KCl < NaCl
