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MaRussiya [10]
3 years ago
6

Acceleration is a vector quantity. O O A. True B. False

Physics
2 answers:
iragen [17]3 years ago
4 0

The answer is A. True, Acceleration is a vector quantit

PtichkaEL [24]3 years ago
3 0
True ( I think ) ............................
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*NEED THIS ANSWERED ASAP*
Musya8 [376]

Answer:

When the velocity is set to a constant value, the displacement increases with time but the acceleration remains zero

Explanation:

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4 0
2 years ago
Hi please help me in this question
Orlov [11]
Well for question 1, the answer would be your opinion on which graph is easier to read and understand better.

for the second question. the one to get specific data would be the table chart because you can read the numbers easily rather than trying to guess on the bar chart wear the bars are actually at are kinda close to an exact number, but not really the number you were thinking
6 0
3 years ago
Which one is having lesser ressistance. a 60w bulb or a 40w bulb?
Ivan
Power dissipation = (voltage across the component)² / (resistance of the component)

Since the resistance is in the denominator of the fraction in this formula for the
quantity of power dissipated, you can see that when the supply voltage is constant,
the smaller resistance dissipates more power.

So the <u>60w bulb</u> has lower resistance than the 40w bulb.
8 0
3 years ago
An airplane starts from rest at the end of a runway and accelerates at a constant rate. In the first second, the airplane travel
Licemer1 [7]

Answer:

v=4.44\frac{m}{s}

Explanation:

Given that the airplane starts from the rest (this is initial velocity equals to zero)  and accelerates at a constant rate, position can be described like this: x=v_{0}t +\frac{1}{2} at^{2} where x is the position, t is the time a is the acceleration and v_{0} is initial velocity. In this way acceleration can be found. a=\frac{2(x-v_{0}t) }{t^{2} } =\frac{2(1.11m-0)}{1s^{2} } =2.22\frac{m}{s^{2} }.

Now we are able to found velocity at any time with the formula: v=v_{0} +at = 0\frac{m}{s} +(2.22\frac{m}{s^{2}}.2s)=4.44\frac{m}{s}

3 0
3 years ago
Dry cells become soft even when not in use. Explain.
mamaluj [8]
This is possible due to self-discharge. Very small internal currents inevitably occur in these cells over time and they will eventually exhaust the chemistry.
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3 years ago
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