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3 years ago

Why doesn't gold react with oxygon

1 answer:

6 0

Give me a thanks I been helped a lot of people and non of them is thanks me.

<span>Gold have a single outer electron. This seems disadvantageous, energy-wise, until you look at the orbitals the electrons are in. The lone electron is in an S-orbital. This orbital is thus half full (since s-orbitals can contain 2 electrons), whereas all the other inner orbitals in silver and gold are filled, and hence exceptionally stable. After a full orbital, the next most stable orbital is a half full one. </span>

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PLEASE HELP MOI I GIVE BRAINIEST

goldenfox [79]

Answer:

If you had alot of winter gear and flash lights due to there being alot of storms on mars and having a glass dome filled with o2 and food then you could have a chance of surviving

Explanation:

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3 years ago

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deff fn [24]

Answer:

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2 years ago

This is the chemical formula for nickel tetracarbonyl (a powerfully poisonous liquid used in nickel refining) Ni(CO)4 A chemical

OverLord2011 [107]

Answer : The number of moles of oxygen present in a sample are 11.3 moles.

Explanation :

The given compound is, $Ni(CO)_4$

By the stoichiometry we can say that, 1 mole of of $Ni(CO)_4$ has 4 moles of CO.

Or we can say that, 1 mole of of $Ni(CO)_4$ has 1 mole of nickel (Ni), 4 moles of carbon (C) and 4 moles of oxygen.

That means,

Number of moles of carbon = Number of moles of oxygen

As we are given that:

Number of moles of carbon = 11.3 moles

So, number of moles of oxygen = number of moles of carbon = 11.3 moles

Therefore, the number of moles of oxygen present in a sample are 11.3 moles.

7 0

3 years ago

Calculate the wavelength, in nanometers, of the light emitted by a hydrogen atom when its electron fallsfrom the n = 7 to the n

Helga [31]

Answer:

λ=2167.6 nm

The wavelength of light emitted is 2167.6 nm.

Explanation:

We recall that Eₙ= $\frac{-2.18*10^{-18} J}{n^{2} }$

since there was transition from n7 to n=4 we will first calculate the change in the energy i.e ΔE

ΔE=E₄-E₇

ΔE= $-2.18*10^{-18} J(\frac{1}{4^{2} } -\frac{1}{7^{2} } )$

ΔE=-9.1760*10^-20 J

Now:

|ΔE|=Energy of photon=h*v=h*c/λ

λ=h*c/|ΔE|

λ= $\frac{6.63*10^{-34}J.s*3.00*10^{8}m/s }{9.1760*10^{-20} J }$

λ=2.1676*10^-6 m

λ=2167.6*10^-9 m

λ=2167.6 nm

The wavelength of light emitted is 2167.6 nm.

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4 years ago

Use the concept of natural selection to explain why organisms typically adapt over time.

CaHeK987 [17]

Organisms is an environment or habitat for species

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3 years ago

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