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loris [4]
3 years ago
13

Why doesn't gold react with oxygon

Chemistry
1 answer:
lara31 [8.8K]3 years ago
6 0
Give me a thanks I been helped a lot of people and non of them is thanks me.

<span>Gold have a single outer electron. This seems disadvantageous, energy-wise, until you look at the orbitals the electrons are in. The lone electron is in an S-orbital. This orbital is thus half full (since s-orbitals can contain 2 electrons), whereas all the other inner orbitals in silver and gold are filled, and hence exceptionally stable. After a full orbital, the next most stable orbital is a half full one. </span>
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A molecule of H2SO4 contains how many atoms?
Margaret [11]

Answer:

2 hydrogen atom, 1 sulfer atom, and 4 oxygen atoms.

6 0
2 years ago
How many grams N2F4 can be produced from 225 g F,?​
zavuch27 [327]

Answer:

308 g

Explanation:

Data given:

mass of Fluorine (F₂) = 225 g

amount of N₂F₄ = ?

Solution:

First we look to the reaction in which Fluorine react with Nitrogen and make N₂F₄

Reaction:

          2F₂ + N₂ -----------> N₂F₄

Now look at the reaction for mole ratio

          2F₂     +    N₂   ----------->  N₂F₄

        2 mole                              1 mole

So it is 2:1 mole ratio of Fluorine to N₂F₄

As we Know

molar mass of F₂ = 2(19) = 38 g/mol

molar mass of N₂F₄ = 2(14) + 4(19) =

molar mass of N₂F₄ = 28 + 76 =104 g/mol

Now convert moles to gram

                 2F₂          +       N₂   ----------->  N₂F₄

        2 mole (38 g/mol)                        1 mole (104 g/mol)

                 76 g                                           104 g

So,

we come to know that 76 g of fluorine gives 104 g of N₂F₄ then how many grams of N₂F₄ will be produce by 225 grams of fluorine.

Apply unity formula

                  76 g of F₂ ≅ 104 g of N₂F₄

                   225 g of F₂ ≅ X of N₂F₄

Do cross multiplication

                  X of N₂F₄ = 104 g x 225 g / 76 g

                  X of N₂F₄ = 308 g

So,

308 g N₂F₄ can be produced from 225 g F₂

7 0
2 years ago
In the following reaction, how many grams of nitroglycerin C3H5(NO3)3 will decompose to give 25 grams of CO2?
gogolik [260]

4C₃H₅(NO₃)₃_{(l)} ------> 12CO₂_{(g)} + 6N₂_{(g)} +  10H₂O_{(g)}  +  O₂_{(g)}

mol of CO₂  =  \frac{mass}{molar mass}

                    =  \frac{25g}{44.01 g/mol}

mol ratio of  CO₂ :  C₃H₅(NO₃)₃

                    12    :     4

∴  if  mole of CO₂  =  0.568 mol

then   "       "   C₃H₅(NO₃)₃  =  \frac{0.568 mol}{12}  *  4

                                           = 0.189 mol


∴ mass of nitroglycerin  =  mole  *  Mr

                                       =  0.189 mol  *  227.0995 g / mol

                                       =  43.00 g

8 0
3 years ago
What is the half-life of a radioisotope?
never [62]
<span>A.The amount of time it takes for half of the material to decay</span>
4 0
3 years ago
Read 2 more answers
Chemical equations are used to model
nataly862011 [7]
Chemical equations give information in two major areas. First, they tell us what substances are reacting (those being used up) and what substances are products (those being made). Second, the coefficients of a balanced equation tell us in what ratio the substances react or are produced.
8 0
3 years ago
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