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Phoenix [80]
3 years ago
13

Fill in the blanks: ______ compounds break up into ______ and ______ in solution, which can move freely and carry an _______ cur

rent.
Chemistry
1 answer:
zmey [24]3 years ago
7 0

I hate virtual school

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A 72.0 mL aliquot of a 1.40 M solution is diluted to a total volume of 248 mL. A 124 mL portion of that solution is diluted by a
Aliun [14]

Answer: 0.20 M

Explanation:

According to the dilution law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 1.40 M

V_1 = volume of stock solution = 72.0 ml

M_2 = molarity of diluted solution = m

V_2 = volume of diluted solution = 248 ml

1.40\times 72.0=m\times 248

m=0.41M

Now 124 mL portion of this prepared solution is diluted by adding 133 mL of water.

According to the dilution law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 0.41 M

V_1 = volume of stock solution = 124 ml

M_2 = molarity of diluted solution = m

V_2 = volume of diluted solution = (124 +133) ml = 257 ml

0.41\times 124=m\times 257

m=0.20M

Thus the final concentration of the solution is 0.20 M.

8 0
4 years ago
A student analyzed an antacid tablet from a bottle containing 120 tablets purchased for $2.79. The mass of the tablet was 1.247
BaLLatris [955]

The cost of one antacid is 2.325 cents per tablet.

<u>Explanation:</u>

As per the question based on the student analysis we know that,

Total antacid tablets in a bottle = 120

Purchase Price of a bottle = $ 2.79

Cost of 1 antacid tablet =\frac{2.79}{120}  

As we know $1 = 100 cent

The cost of 1 antacid tablet = \frac{2.79}{120} × 100 cents = 2.325 cents/tablet .

Thus we came to know that it costs 2.325 cents/tablet .

5 0
3 years ago
The two most abundant elements in earth's core are ?
vesna_86 [32]
The two most abundant elements in Earths core are Iron and Nickel.

Hope this helps!
3 0
4 years ago
Read 2 more answers
Suppose that 0.50 grams of barium-131 are administered orally to a patient. Approximately how many milligrams of the barium woul
nalin [4]

Two months later 13.8 milligrams of the barium-131 still be radioactive.

<h3>How is the decay rate of a radioactive substance expressed ? </h3>

It is expressed as:

A = A_{0} \times (\frac{1}{2})^{t/T}

where,

A = Amount remaining

A₀ = Initial Amount

t = time

T = Half life

Here

A₀ = 0.50g

t  = 2 months = 60 days

T = 11.6 days  

Now put the values in above expression we get

A = A_{0} \times (\frac{1}{2})^{t/T}

   = 0.50 \times (\frac{1}{2})^{60/11.6}

   = 0.50 \times (\frac{1}{2})^{5.17}

   = 0.50 × 0.0277

   = 0.0138 g

   = 13.8 mg          [1 mg = 1000 g]

Thus from the above conclusion we can say that Two months later 13.8 milligrams of the barium-131 still be radioactive.

Learn more about the Radioactive here: brainly.com/question/2320811

#SPJ1

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Suppose that 0.50 grams of ban that 0.50 grams of barium-131 are administered orally to a patient. Approximately many milligrams of the barium would still be radioactive two months later? The half-life of barium-131 is 11.6 days.

3 0
2 years ago
11.
alisha [4.7K]
11. Atomic number

12. in the nucleus with neutrons
6 0
3 years ago
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