Answer:
Ka = 4.76108
Explanation:
- CO(g) + 2H2(g) ↔ CH3OH(g)
∴ Keq = [CH3OH(g)] / [H2(g)]²[CO(g)]
[ ]initial change [ ]eq
CO(g) 0.27 M 0.27 - x 0.27 - x
H2(g) 0.49 M 0.49 - x 0.49 - x
CH3OH(g) 0 0 + x x = 0.11 M
replacing in Ka:
⇒ Ka = ( x ) / (0.49 - x)²(0.27 - x)
⇒ Ka = (0.11) / (0.49 - 0.11)² (0.27 - 0.11)
⇒ Ka = (0.11) / (0.38)²(0.16)
⇒ Ka = 4.76108
The main reason for this is Average bond of O₂ is shorter and strong from O₃.
<h3>What is ozone?</h3>
Ozone is a blue gas composed of three oxygen atoms bonded together.
It occurs naturally high up in the Earth's atmosphere, where it protects the surface from harmful ultraviolet (UV) rays,
UV radiation will dissociate ozone into an oxygen atom and an oxygen molecule.
Ozone molecules are tetrahedral so the bond angle is 109 degree the electrons in the double bond occupy more space that the non-bonding electron pair.
Oxygen has a small size that leads to smaller O-O bond length.
A lone pair of electrons on both the oxygen repel each other leading to weakening of O-O bond.
O3 has longer and weaker bonds than O2, whereas SO2 has shorter and stronger bonds than SO.
Molecular oxygen, O2, is photolyzed by light of 241 nm and has a bond energy of 498 kJ/mol.
The main reason for this is Average bond of O₂ is shorter and strong from O₃.
Learn more about ozone, Here:
brainly.com/question/27911475
#SPJ4
I think so. You should check the Periodic Table. ;-)
Answer:
B
Explanation:
The particles are bound to each other and they vibrate at an almost undetectable rate.
Answer:
Explanation:
Hello,
In this case, since you have both the final and initial volume for the titration procedure, clearly, the used volume is computed by the subtraction between them, since it accounts for the employed volume of the base, it turns out:
Best regards.
