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3 years ago

Which choice names the two parts of Earth that make up the lithosphere?

Physics

2 answers:

professor190 [17]3 years ago

8 0

Answer:

<h2>Crust and outer part of mantle.</h2>

Explanation:

The lithosphere is the solid and outer part of the Earth. Includes the upper portion of the mantle and the crust, which are the outer layers of the Earth, that's why is commonly defined as the hard part of the Earth, refer to the image attached to see it better.

In addition, we could divide the lithosphere in two parts: oceanic and continental. The oceanic lithosphere is denser than the continental lithosphere and it's linked to the oceanic crust. All these parts comprehend the tectonic plates, which are the most known part of the lithosphere, because is most familiarize with their movements.

Therefore, the correct answer would be: Crust and outer part of mantle are the two parts that make up the lithosphere.

SIZIF [17.4K]3 years ago

6 0

The lithosphere includes the crust, and the mantle :)

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How does charging by conduction occur?

lutik1710 [3]

Answer : (A) A charged object is brought near a neutral object without touching it.

Explanation:

Bodies can be charged by the method of conduction. By conduction the body acquires the same charge as on the charging body.

Charging the body can be understood by the following example of charging a paper cylinder by conduction. Make a paper cylinder by rolling a strip of paper on a pencil and then gently pulling out the pencil. Suspend the paper cylinder by a string tied to its center, now touch the paper cylinder with a glass rod rubbed with silk so it has a positive charge. Remove the class rod and the again bring it near to the paper cylinder.

The paper cylinder is repelled by the positively charged rod. And when you bring a negatively rubbed rod, next to the cylinder it will be attracted towards the rod. This means that the paper cylinder has acquired a positive charge as on the glass rod due to conduction.

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3 years ago

A 1200-kg SUV is moving alone a straight highway at 12.0 m/s. Another car, with mass 1800 kg and speed 20.0 m/s, has its center

andreev551 [17]

Answer:

A) d = 24 m

B) 50400 kg.m/s

C) v₀ = 16.8 m/s

D) 50400 kg.m/s. It's equal to the momentum found in part B.

Explanation:

We are given;

Mass of station wagon;m1 = 1200 kg Velocity; V = 12 m/s

Mass of car; m2 = 1800 kg

Velocity of car; v2 = 20 m/s

a ) Let centre of mass of car and station wagon be at a distance d from wagon

Thus,

If we take moment of weight about it, we have;

1200 x d = 1800 x ( 40 - d )

Where, d is the position of the center of mass of the system consisting of the two cars

Thus,

1200d = 72000 - 1800d

1200d + 1800d = 72000

3000 d = 72,000

d = 72,000/3000

d = 24 m

b ) Total momentum= m1•v1 + m2•v2

= (1200 x 12) + (1800 x 20)

= 14400 + 36000

= 50400 kg.m/s

c ) Let speed of centre of mass be v₀

Thus,

v₀ = (m1•v1 + m2•v2)/(m1 + m2)

v₀ = 50400/(1200 + 1800)

v₀ = 50400/3000

v₀ = 16.8 m/s

d) System Total momentum = velocity of centre mass x total mass

Thus,

Total momentum = v₀(m1 + m2)

= 16.8(3000) = 50400 kg.m/s .

This value is equal to what was calculated in part b

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