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Kay [80]
3 years ago
10

Which choice names the two parts of Earth that make up the lithosphere?

Physics
2 answers:
professor190 [17]3 years ago
8 0

Answer:

<h2>Crust and outer part of mantle.</h2>

Explanation:

The lithosphere is the solid and outer part of the Earth. Includes the upper portion of the mantle and the crust, which are the outer layers of the Earth, that's why is commonly defined as the hard part of the Earth, refer to the image attached to see it better.

In addition, we could divide the lithosphere in two parts: oceanic and continental. The oceanic lithosphere is denser than the continental lithosphere and it's linked to the oceanic crust. All these parts comprehend the tectonic plates, which are the most known part of the lithosphere, because is most familiarize with their movements.

Therefore, the correct answer would be: Crust and outer part of mantle are the two parts that make up the lithosphere.

SIZIF [17.4K]3 years ago
6 0
The lithosphere includes the crust, and the mantle :)
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Didifference between uniform and variable velocity <br>​
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Answer:

Uniform velocity is scalar , while variable velocity is vector

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2 years ago
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Please, help!!
pashok25 [27]

Answer:

The net force in the middle particle is zero, and it has no direction.

Explanation:

First, the force that one charge does in other charge is:

F = K*q1*q2/r^2

where k is a constant, q1 and q2 are the charges, and r is the distance between the charges.

If the force is positive, the force is repulsive (pushes away the charge) if the force is negative, is attractive.

Now, we have that the middle charge has a charge of 4.00nC, and in each side at a distance of 4m, has a charge of 4.00nC.

i will write qL as the charge in the left, qR as the charge in the right, and qM as the charge in the middle.

The force that the charge in the right does to the charge in the middle is:

Fr = (k*(4.00nC)^2)/4m^2 = k*(nC/m)^2

And is positive, so this is a repulsive force, this means that if the charge is at the right of the middle charge, then this force pushes the middle charge to the left.

For the left charge we have the same:

Fl = (k*(4.00nC)^2)/4m^2 = k*(nC/m)^2

But in this case, the force pushes the particle to the right, then this force, that is equal in magnitude to the previous force, pushes it in the opposite direction, then the total force in the middle particle is anulated. This is because the two external particles are "pushing" the middle particle with the same force and in the opposite direction.

6 0
2 years ago
An aluminum cup of mass 150 g contains 800 g of water in thermal equilibrium at 80.0°C. The combination of cup and water is cool
gladu [14]

Answer:

Heat Flow Rate : ( About ) 87 W

Explanation:

The heat flowing out of the system each minute, will be represented by the following equation,

Q( cup ) + Q( water ) = m( cup ) * c( al ) * ΔT + m( w ) * c( w ) * ΔT

So as you can see, the mass of the aluminum cup is 150 grams. For convenience, let us convert that into kilograms,

150 grams = .15 kilograms - respectively let us convert the mass of water to kilograms,

800 grams = .8 kilograms

Now remember that the specific heat of aluminum is 900 J / kg * K, and the specific heat of water = 4186 J / kg * K. Therefore let us solve for " the heat flowing out of the system per minute, "

Q( cup ) + Q( water ) = .15 * ( 900 J / kg * K )  * 1.5 + .8 * ( 4186 J / kg * K ) * 1.5,

Q( cup ) + Q( water ) = 5225.7 Joules

And the heat flow rate should be Joules per minute,

5225.7 Joules / 60 seconds = ( About ) 87 W

5 0
3 years ago
K-2/5=11k literal equations
krek1111 [17]
-2/5 = 11k - k
-2/5 = 10k
-2/5/10 = k
-2/5 * 10 = k
-2/50 = k
k = -1/25.

-1/25 - 2/5 = 11k is true.
6 0
3 years ago
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