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prisoha [69]
3 years ago
12

Draw the product formed when oleic acid is hydrogenated.

Chemistry
1 answer:
lesya [120]3 years ago
7 0

Oleic acid belongs to class of alkene and in alkenes, addition of H-H across C=C that is carbon carbon double bond results in the formation of alkane as a product in the presence of specific catalyst such as nickel, palladium and platinum.  The reaction is said to be hydrogenation reaction.

Oleic acid (C_{17}H_{33}COOH) consist of 17 carbon atoms attached to 33 hydrogen atoms with one double bond between two carbon atoms and one carboxylic group i.e.(-COOH). When oleic acid is hydrogenated or reacts with hydrogen in the presence of catalyst, then the carbon carbon double breaks by the addition H-H and alkane product i.e. stearic acid  (C_{17}H_{35}COOH) is formed.

The chemical reaction is shown in the image.

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<h3>Solution:</h3>

[\text{H}^{+}] = 10^{-\text{pH}}

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Answer:

10 L

Explanation:

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p1V1 = p2V2

Data:

p1 = 125 atm; V1  = 4.0 L  

p2 =  50 atm; V2 = ?

Calculation:

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5 0
3 years ago
You are a NASCAR pit crew member. Your employer is leading the race with 20 laps to go. He just finished a pit stop and has 5.0
jek_recluse [69]

Answer:

Since there are 3500 g of fuel left in the tank, and he needs only 1687.5 g to complete 20 laps, he has enough fuel to complete the race. I will tell the driver that he does not need to make another pit stop as he has enough fuel to complete the race.

Explanation:

Density = mass / volume

Density of fuel = 700 g/ 1 gal

Therefore, the mass of fuel in 1 gallon = 700 g

The driver has 5.0 gallons of fuel in the tank.

The mass of 5.0 gallons of fuel = 5 × 700 = 3500 g of fuel

Equation of the combustion of fuel, C₅H₁₂ is given below:

C₅H₁₂ + 8 O₂ ---> 6 H₂O + 5 CO₂

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8 moles of O₂ has a mass = 256 g

Therefore, 300 g of O₂ will require 300 × (72/256) g of C₅H₁₂ = 84.375 g of C₅H₁₂

84.375 g of fuel is used by the car per lap;

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Since there are 3500 g of fuel left in the tank, and he needs only 1687.5 g to complete 20 laps, he has enough fuel to complete the race. I will tell the driver that he does not need to make another pit stop as he has enough fuel to complete the race.

7 0
3 years ago
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3 years ago
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