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3 years ago

Ligus

Physics

2 answers:

GREYUIT [131]3 years ago

6 0

Answer:it’s 0N

Explanation:i just did it

Travka [436]3 years ago

4 0

Answer:

Well that depends on the force that is being applied onto the table and how much is being forced back

Explanation:

When learning about net force there should be some numbers with a N next to them showing you the direction of the newtons. In order to solve this problem and figure out the net force you have to subtract the newtons ( larger number first no negative newtons) then the largest newton after the subtraction the direction is the same direction as the biggest number

Example: 20N⬆️

30N⬇️

Subtract 30-20=10N⬇️

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Brad has three beakers of water. Each beaker contains 500 mL of water. The temperature of the water in the first beaker is 40°C.

dexar [7]

Explanation:

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7 0

3 years ago

The index of refraction for red light in water is 1.331 and that for blue light is 1.340. A ray of white light enters the water

Alex Ar [27]

Answer:

(a) 47.08°

(b) 47.50°

Explanation:

Angle of incidence = 78.9°

<u>For blue light : </u>

Using Snell's law as:

$\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}$

Where,

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₂ is the refractive index for blue light which is 1.340

n₁ is the refractive index of air which is 1

So,

$\frac {sin\theta_2}{sin{78.9}^0}=\frac {1}{1.340}$

${sin\theta_2}=0.7323$

Angle of refraction for blue light = sin⁻¹ 0.7323 = 47.08°.

<u>For red light : </u>

Using Snell's law as:

$\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}$

Where,

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₂ is the refractive index for red light which is 1.331

n₁ is the refractive index of air which is 1

So,

$\frac {sin\theta_2}{sin{78.9}^0}=\frac {1}{1.331}$

${sin\theta_2}=0.7373$

Angle of refraction for red light = sin⁻¹ 0.7373 = 47.50°.

5 0

4 years ago

Which of the following Resistors A, B, C or D, would use the least power? Make

Westkost [7]

i think the answer is D 10.0

4 0

3 years ago

An electromagnetic wave in a vacuum traveling in the +x direction generated by a variable source initially has a wavelength λ of

djverab [1.8K]

Answer:

B = E/c = 14.04T₁ = 11 pT

Explanation:

We know c = E/B where E = maximum electric field = 3.30 × 10⁻³ V/m, B = maximum magnetic field and c = speed of light

B = E/c also c = fλ = λ/T where λ = wavelength = 235 μm = 235 × 10⁻⁶ m and T = period

c = λ₁/T₁ = λ₂/T₂ T₂ = 2.8T₁ where λ₁,λ₂ are the initial and final wavelengths and T₁,T₂ are the initial and final periods.

T₁ = λ₁/c = 235 × 10⁻⁶ m/3 × 10⁸ m/s = 7.833 × 10⁻¹³ s = 0.7833 ps

T₂ = 2.8T₁ = 2.8 × 7.833 × 10⁻¹³ s = 21.93 × 10⁻¹³ s = 2.193 ps

λ₁/T₁ = λ₂/2.8T₁

λ₂ = 2.8λ₁ = 2.8 × 235 μm = 658 μm

c = λ₂/T₂ = 2.8λ₁/2.8T₁ = λ₁/T₁ , since the speed of light c is constant.

B = E/c = E/λ₁/T₁ = ET₁/λ₁

B = ET₁/λ₁ = 3.30 × 10⁻³ V/m × T₁/235 × 10⁻⁶ m = 14.04T₁ Tesla

B = 14.04 × 7.833 × 10⁻¹³ s = 10.99 × 10⁻¹² T ≅ 11 pT

5 0

4 years ago

The bending of a wave as it enters a new medium at an angle is called _____.

Andru [333]

Answer:

C). Refraction

Explanation:

When light enters from one medium to another medium then it changes it's direction from its initial direction

the phenomenon of changing the direction due to change in the medium is known as Refraction of light

So here we know that when light strikes an interface which separates two medium then due to change in the medium we will have

$\mu_1 sin\theta_1 = \mu_2 sin\theta_2$

so here we have

$\theta_1, \theta_2$ = two angles of the light in two mediums

$\mu_1 , \mu_2$ = two refractive index of the two mediums

So correct answer will be

C). Refraction

4 0

3 years ago