Hello : let : y = f(x) so : y' = f'(x)
calculate : f'(x) and : f'(-1) given f(-1) = 2
by derivate : <span>4x3+2y2−11=4xy−x
12x² +4yy' = 4y +4xy' - 1
4yy' - 4xy' = - 12x² +4y -1
y' ( 4y - 4x) = 4y -12x² -1 ...(*)
if x = -1 y = 2 subsct in : (*)
y' (4(2)-4(-1)) = 4(2)-12(-1)² - 1
2y' = - 9
y' = - 9/2 = f'(- 1) ( the slope of the tangent )
</span>of the tangent line to the curve <span>at the point (−1,2) is :
y - 2 = (-9/2)(x +1)</span>
Tanα=h/x
x=h/tanα
x=70/tan38 ft
x≈89.6 ft (to nearest tenth of a foot)
Note: the question seems strange, (because this would make the ladder almost 114 feet long!) or are we to assume as I did that the ladder is leaning against a point 70 feet high, or should if be a 70 foot ladder leaning against a wall of unknown height?
If it is just a 70 ft ladder at a 38° inclination the:
cosα=x/L
x=Lcosα
x=70cos38° ft
x≈55.2 ft
4g = 24
First, divide both sides by 4. / Your problem should look like: g =
Second, simplify
to 6. / Your problem should look like: g = 6
Answer:
g = 6
Answer:
B. Pentagon
Step-by-step explanation:
Pentagon (figure having 5 sides) is the shape of the cross-section of the figure.
Answer:
I have no idea what that means but okayyy
Step-by-step explanation:
:)
