Question

Ill mark as brainliest if given the option

Answer 1

Answer:

$36 g/cm^{3}$

Explanation:

In order to find the density, the problem says we need to find the volume first.

Since we know that the sample of gold is a perfect cube, we know that the side lengths will all be the same. Since all the side lengths will be 3, we can take that value and cube it to find the volume.

$3^{3} = 27$

Now that we know the volume is 27 cm³, we can solve find the density.

$Density = \frac{Mass}{Volume}$

$Density = \frac{972g}{27cm^{3} } = 36 g/cm^{3}$

Therefore, the density of the sample is 36 g/cm³.