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SVETLANKA909090 [29]
3 years ago
9

Currently, the lost time of each stage is 4 seconds, and intersection critical v/c ratio is set to be 0.75 to avoid cycle failur

es caused by randomness of arrival traffic. Solve the following problems: 1) identify critical lane groups and solve their sum of flow ratios; 2) minimum cycle length and optimal cycle length; 3) Autonomous vehicle technologies make traffic movement at intersections more efficient. The lost time of each stage is reduced to 2 seconds, saturation headway is reduced by 10%. If the intersection demand does not change, calculate the critical v/c ratio corresponding to the minimum cycle length in 2).

Engineering
1 answer:
KIM [24]3 years ago
7 0

Find the solution in the attachments

Note: Question was incomplete, so the complete question is added in the attachments.

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A 0.50 m3 drum was filled with 0.49 m3 of liquid water at 25oC and the remaining volume was water vapor without any air. The dru
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There is not going to be pressure build up in the  system,that is isobaric process.

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What is one of the most common ways workers get hurt around machines
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For some transformation having kinetics that obey the Avrami equation, the parameter n is known to have a value of 2. If, after
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This question is incomplete, the complete question is;

For some transformation having kinetics that obey the Avrami equation, the parameter n is known to have a value of 2. If, after 100 s, the reaction is 40% complete, how long (total time in seconds) will it take the transformation to go to 95% completion

y = 1 - exp( -ktⁿ )

Answer: the time required for 95% transformation is 242.17 s

Explanation:

First, we calculate the value of k which is the dependent variable in Avrami equation

y = 1 - exp( -ktⁿ )

exp( -ktⁿ ) = 1 - y

-ktⁿ = In( 1 - y )

k = - In( 1 - y ) / tⁿ

now given that; n = 2, y = 40% = 0.40, and t = 100 s

we substitute

k = - In( 1 - 0.40 ) / 100²

k = - In(0.60) / 10000

k = 0.5108 / 10000

k = 0.00005108 ≈ 5.108 × 10⁻⁵

Now calculate the time required for 95% transformation

tⁿ = - In( 1 - y ) / k

t = [- In( 1 - y ) / k ]^1/n

n = 2, y = 95% = 0.95 and k = 5.108 × 10⁻⁵

we substitute our values

t = [- In( 1 - 0.95 ) / 5.108 × 10⁻⁵ ]^1/2

t = [2.9957 / 5.108 × 10⁻⁵]^1/2

t = [ 58647.22 ]^1/2

t = 242.17 s

Therefore the time required for 95% transformation is 242.17 s

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3 years ago
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