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weqwewe [10]
3 years ago
15

A diffraction grating with 200 lines per mm is used in an experiment to study the visible spectrum of a gas discharge tube. At w

hat angle from the beam axis will the first order peak occur if the tube emits light with wavelength of 617.3 nm
Physics
1 answer:
inna [77]3 years ago
5 0

Answer

123.5 x 10 ^-3 radian

Explanation:

Given the Width of slit a = 1 x 10⁻³ / 200

a = 5x 10⁻⁶ m .

angle at which first order peak is formed

= λ / a (where λ is wavelength and a is width of slit)

given λ = 617.3 x 10⁻⁹ m

a = 5 x 10⁻⁶

θ = 617.3 x 10⁻⁹ / 5 x 10⁻⁶

= 123.5x 10⁻³ radian .

first order peak is formed at an angle of 123.5 x 10⁻³ radian .

Explanation:

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A projectile is shot from the edge of a cliff 80 m above ground level with an initial speed of 60 m/sec at an angle of 30° with
Dvinal [7]

Answer:

8 seconds

Explanation:

Answer:

Explanation:

Going up

Time taken to reach maximum height= usin∅/g

=3 secs

Maximum height= H+[(usin∅)²/2g]

=80+[(60sin30)²/20]

=125 meters

Coming Down

Maximum height= ½gt²

125= ½(10)(t²)

t=5 secs

6 0
3 years ago
n ultraviolet light beam having a wavelength of 130 nm is incident on a molybdenum surface with a work function of 4.2 eV. How f
pashok25 [27]

Answer:

The speed of the electron is 1.371 x 10⁶ m/s.

Explanation:

Given;

wavelength of the ultraviolet light beam, λ = 130 nm = 130 x 10⁻⁹ m

the work function of the molybdenum surface, W₀ = 4.2 eV = 6.728 x 10⁻¹⁹ J

The energy of the incident light is given by;

E = hf

where;

h is Planck's constant = 6.626 x 10⁻³⁴ J/s

f = c / λ

E = \frac{hc}{\lambda} \\\\E = \frac{6.626*10^{-34} *3*10^{8}}{130*10^{-9}} \\\\E = 15.291*10^{-19} \ J

Photo electric effect equation is given by;

E = W₀ + K.E

Where;

K.E is the kinetic energy of the emitted electron

K.E = E - W₀

K.E = 15.291 x 10⁻¹⁹ J - 6.728 x 10⁻¹⁹ J

K.E = 8.563 x 10⁻¹⁹ J

Kinetic energy of the emitted electron is given by;

K.E = ¹/₂mv²

where;

m is mass of the electron = 9.11 x 10⁻³¹ kg

v is the speed of the electron

v = \sqrt{\frac{2K.E}{m} } \\\\v =  \sqrt{\frac{2*8.563*10^{-19}}{9.11*10^{-31}}}\\\\v = 1.371 *10^{6} \ m/s

Therefore, the speed of the electron is 1.371 x 10⁶ m/s.

8 0
3 years ago
Q1: A cyclist brakes to a stop. His thinking distance was 1m and his braking distance was 3m. What was his overall stopping dist
weeeeeb [17]

Answer:

1.) 4m

2.) 37 m

3.) 62m

4.) 2.5 s

Explanation:

1.) Given that the

Thinking distance = 1m

Breaking distance = 3m

Stopping distance = breaking distance + thinking distance

Stopping distance = 1 + 3 = 4m

2.) Given that the

Stopping distance = 52 m

Thinking distance = 15m

Breaking distance = 52 - 15 = 37m

3.) The stopping distance = 76m

Thinking distance = 14m

Breaking distance = 76 - 14 = 62m

It take the brakes 62m to slow the car down to a stop.

4.) Given that a lorry travels 28m when stopping from a speed of 4m/s. If its braking distance was 18m, what was the driver’s reaction time?

Thinking = stopping distance - braking distance

Thinking distance = 28 - 18 = 10m

Speed = distance/time

4 = 10/reaction time

Reaction time = 10/4

Reaction time = 2.5 s

5.) Question incomplete

5 0
3 years ago
A 17 H inductor carries a current of 1.8 A. At what rate must the current be changed to produce a 70 V emf in the inductor?
pogonyaev

Answer:

at rate the current change is 6.75 A / sec

Explanation:

given data

inductance L  = 17 H

current I = 1.8 A

emf  e = 70 V

to find out

At what rate must the current be changed

solution

we will apply here emf formula that is

emf =  inductance (di/dt)

so  here (di/dt)  will be

di/dt = emf  /  inductance    .......................1

put  value of emf and inductance in equation 1 we get rate

di/dt = 81 / 12

di/dt = 6.75 A / sec

so at rate the current change is 6.75 A / sec

5 0
3 years ago
The filament temperature of a light bulb is 2 000 K when the bulb delivers 40 W of power.
lesya692 [45]

Answer:

c. 98 W

Explanation:

P_{i} = initial power delivered by bulb at initial temperature = 40 W

T_{i} = initial temperature of filament = 2000 K

Now the temperature of filament of the bulb rises

P_{f} =Final power delivered by bulb at higher temperature

T_{f} = Final higher temperature of filament = 2500 K

As per Stefan's law, the power delivered by the bulb depends directly on fourth power of the temperature. hence we can write

\frac{P_{f}}{P_{i}} = \frac{T_{f}^{4} }{T_{i}^{4}} \\\frac{P_{f}}{40} = \frac{2500^{4} }{2000^{4}}\\\\P_{f} = (2.44) (40)\\P_{f} = 98 W

6 0
3 years ago
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