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Anna11 [10]
3 years ago
11

A softball player moving 3.89 m/s

Physics
1 answer:
guapka [62]3 years ago
7 0

Answer:

0.119 s is the correct answer to this question.

Explanation:

As mentioned in the question

U=3.89\ m/s

a=-1.44\ m/s^2

S=4.8\ m

Consider the final speed of the softball covering the distance of 4.8m is v

Now using the equation

v^2=U^2+2aS

Putting the value of U, A, S in the previous equation we get

V^2=3.89^2-2\times 1.44\times 4.8\\V=3.7\ m/s\\

Now again using the equation

v=U+at

where U=intial velocity, t= time

Substituting the value of v, U, a

3.7=3.89-1.44\times t\\t=0.119\ s\\

Hence the slide time is 0.119 s

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Someone please help<br> Just need answers
marishachu [46]

Answer:

As follows,

Explanation:

KE=1/2mv^2

In 1st question,

KE=1/2mv^2=1/2*0.05*12=0.3 J [50g=0.05 kg]

In 2nd question,

KE=1/2mv^2

6.8=1/2*0.046*v^2

v=sqrt(6.8/0.023)

v=17.19

In 3rd question,

KE=1/2mv^2

63/392=m

m=0.16kg=160g

For 4th,

a.

1st case,

KE=1/2mv^2=1/2*28*2.4^2=80.64

2nd case,

KE=1/2mv^2=1/2*28*3.7^2=191.66

Change in KE=191.66-80.64=11.02

b.Speed/velocity gained

6 0
3 years ago
Information about climate change?​
Kamila [148]
The term climate change encompasses global warming, but refers to the broader range of changes that are happening to our planet. , These broader climate changes include: rising sea levels, shrinking mountain glaciers, accelerating ice melt in Greenland, Antarctica and the Arctic, and shifts in flower and plant blooming times.
5 0
3 years ago
a railroad tie weights 920 N and is 2.6 m long. How much force is required to: pick it up off the ground? lift one end and rotat
lukranit [14]

1) The minimum force needed is 920 N

2) The minimum force is 460 N

3) The minimum force is 598 N

Explanation:

1)

We can answer this part by simply looking at the forces involved. In fact, there are two forces acting on the railroad:

  • Its weight, W, acting downward
  • The force applied to lift it, F, upward

So the net force on the railroad is

\sum F = F - W

where

W = 920 N is the weight of the railroad

In order to lift the railroad, the net force must be upward, so

\sum F \geq 0

And therefore

F\geq W

which means that the minimum force needed is equal to the weight of the railroad, 920 N.

2)

In this case, we have to use the principle of equilibrium of moments.

In fact, when the railroad rotates uniformly (=constant angular speed) about its end, it means that the moment produced by the weight (acting in one direction) is equal to the moment produced by the force applied (acting in the other direction). Therefore, we can write:

W \frac{L}{2} = F L

where

W = 920 N is the weight

L = 2.6 m is the length of the railroad

F is the force applied

We wrote L/2 on the left of the equation because the weight acts at the center of mass of the railroad (located at the midpoint), while on the right it is L because the force F is applied at the end of the railroad.

Solving for F,

F=\frac{W}{2}=\frac{920}{2}=460 N

3)

This problem is similar to the previous part, however in this case, the force applied F is applied 0.6 m from the end, pivoting around the opposite end.

This means that the distance between the point of application of the force F and the pivot is

L' = L - 0.6

where

L = 2.6 m

Therefore the equation for the equilibrium of moments becomes

W\frac{L}{2}=F(L-0.6)

and substituting

W = 920 N

L = 2.6

We find the magnitude of F:

W\frac{2.6}{2}=F(2.6-0.6)\\1.3W = 2F\\F=\frac{1.3}{2}W=\frac{1.3}{2}(920)=598 N

Learn more about forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

4 0
3 years ago
True or False: Friction makes energy vanish. Explain your answer!
Sidana [21]
False because friction will generate heat energy and/or sound energy etc. Think of a car stopping or a broom sweeping the ground.
8 0
4 years ago
17. A 120 m long train is moving in a direction with speed 20 m/s. A train B moving with 30
nydimaria [60]
Answer is D.

Speed:
Use relative speed to simplify the situation. Since the trains are moving in opposite directions, you can add the speeds and pretend the first train is stationary (moving at 0m/s) and the second train is moving at 50m/s.

Distance:
The front of the second train needs to travel 120m to get from the front to the back of the first train. When the front of the second train is at the back of the first train, the back of the second train is still 10m in front of the first train. The back therefore has to travel 130m to clear the first train. The total distance over which the trains are overlapping in this scenario is therefore 120 + 130 = 250m.

You have speed and you have distance so now just calculate time:

v = d / t
50 = 250 / t
t = 5s
4 0
3 years ago
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