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Radda [10]
4 years ago
14

If we decrease the distance traveled over the same period of time, this will ________. Choices: decrease the speed.. . increase

the velocity.. . increase the speed.. . have no effect on speed or velocity.
Physics
2 answers:
nikklg [1K]4 years ago
8 0

If we decrease the distance traveled over the same period of time, this will ________.

Answer:

A. Decrease in Speed

Explanation:

You slowing down the distance over time so that will decrease your speed.

Serhud [2]4 years ago
5 0
Speed is the sum of distance divided by time (speed = distance / time). So if you were to decrease the distance traveled over the same period of time, this will decrease the speed. If either distance or time is increased or decreased, the speed will do the same. 
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Examples of increase in pressure due to increase in applied force<br>​
Nina [5.8K]

Answer:

injecting

Explanation:

5 0
3 years ago
A reciprocating compressor is a device that compresses air by a back-and-forth straight-line motion, like a piston in a cylinder
QveST [7]

Answer:

\Delta \theta = 47.57^{\circ} C

Explanation:

given,

moles of air compressed, n = 1.70 mol

initial temperature, T₁ = 390 K

Power supply by the compressor, P = 7.5 kW

Heat removed = 1.3 kW

Angular frequency of the compressor, f = 110 rpm = 110/60 = 1.833 rps.

Time of compression = time of the hay revolution

             =\dfrac{1}{2}\ T

             =\dfrac{1}{2}\times \dfrac{1}{f}

             =\dfrac{1}{2}\times \dfrac{1}{1.833}

             =0.273 s

Using first law of thermodynamics

U = Q - W

now,

\dfrac{\Delta U}{\Delta t} = \dfrac{\Delta Q}{\Delta t}- \dfrac{\Delta W}{\Delta t}

Power supplied \dfrac{\Delta W}{\Delta t} = 7.5 kW

heat removed \dfrac{\Delta Q}{\Delta t} = 1.3 kW

now,

\dfrac{\Delta U}{\Delta t} = 7.5 -1.3

\dfrac{\Delta U}{\Delta t} = 6.2 kW

we know,

\dfrac{\Delta U}{\Delta t}=\dfrac{nC_v\Delta \theta}{\Delta t}

 C_v for air = 5 cal/° mol

                   = 5 x 4.186 J/mol°C  = 20.93 J/mol°C

now,

\Delta \theta = \dfrac{\Delta U}{\Deta t}\times \dfrac{\Delta t}{n C_v}

\Delta \theta = 6.2\times 10^3 \times \dfrac{0.273}{1.7\times 20.93}

\Delta \theta = 47.57^{\circ} C

the temperature change per compression stroke is equal to 47.57°C.

4 0
3 years ago
Yosef is playing with different kinds of rubber bands. Some are very narrow and some are quite wide. Yosef is curious about the
kari74 [83]

Answer:

He could have many different hypothesis, but here is one.

Explanation:

If rubber bands are wider, then the rubber bands will stretch further, because the wider a rubber band is the stronger it is.

4 0
3 years ago
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The electrons are in the electron cloud the different field will either wanna connect or not 
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3 years ago
What distance is moved if we have a 8N force and the work done is 90J
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