Magnitude of player’s average acceleration is .
Further Explanation:
The player follows the Newton’s law of motion while jumping above the ground.
Given:
The vertical distance covered is .
Weight of the player is .
Time taken to change the momentum is .
Concept:
The mass of the player is given as:
Substitute the values of weight and acceleraton due to gravity.
To calculate the initial velocity of jump when final velocity, acceleration and distance covered is given, apply the Newton equation of motion given as:
Rearrange the above equation for initial velocity .
Here, is the final velocity, is the initial velocity, is the displacement and is the acceleration.
Substitute for , for and for in the above equation.
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Taking square root on both sides, we get
:
We know that, Force is equal to the rate of change of momentum
Write the equation for relation between force and momentum:
Substitute for , for , for and for in above equation.
To lift the body of player, he needs to apply a force equal to his weight on the ground.
Total force applied by the player on the ground is:
Here, is the total force applied on the body.
Magnitude of average acceleration:
Thus, the magnitude of player’s average acceleration is .
Learn more:
1. Find the odd one out for lever: brainly.com/question/1073452
2. Principle of conservation of momentum: brainly.com/question/9484203
3. Motion on the rough surface against friction: brainly.com/question/7031524
Answer Details:
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords:
Basketball player, Darrell, Griffith, record, vertical jump, 1.2 m (4 ft), 890 N, feet, 0.300 s, magnitude, average acceleration, the floor, momentum, force, velocity, 200 lb, time.