What Is The Meaning Of Life

Air is compressed from an inlet condition of 100 kPa, 300 K to an exit pressure of 1000 kPa by an internally reversible compress

ElenaW [278]

Answer:

(a) $W_{isoentropic}=8.125\frac{kJ}{mol}$

(b) $W_{polytropic}=7.579\frac{kJ}{mol}$

(c) $W_{isothermal}=5.743\frac{kJ}{mol}$

Explanation:

Hello,

(a) In this case, since entropy remains unchanged, the constant $k$ should be computed for air as an ideal gas by:

$\frac{R}{Cp_{air}}=1-\frac{1}{k} \\\\\frac{8.314}{29.11} =1-\frac{1}{k}\\$

$0.2856=1-\frac{1}{k}\\\\k=1.4$

Next, we compute the final temperature:

$T_2=T_1(\frac{p_2}{p_1} )^{1-1/k}=300K(\frac{1000kPa}{100kPa} )^{1-1/1.4}=579.21K$

Thus, the work is computed by:

$W_{isoentropic}=\frac{kR(T_2-T_1)}{k-1} =\frac{1.4*8.314\frac{J}{mol*K}(579.21K-300K)}{1.4-1}\\\\W_{isoentropic}=8.125\frac{kJ}{mol}$

(b) In this case, since $n$ is given, we compute the final temperature as well:

$T_2=T_1(\frac{p_2}{p_1} )^{1-1/n}=300K(\frac{1000kPa}{100kPa} )^{1-1/1.3}=510.38K$

And the isentropic work:

$W_{polytropic}=\frac{nR(T_2-T_1)}{n-1} =\frac{1.3*8.314\frac{J}{mol*K}(510.38-300K)}{1.3-1}\\\\W_{polytropic}=7.579\frac{kJ}{mol}$

(c) Finally, for isothermal, final temperature is not required as it could be computed as:

$W_{isothermal}=RTln(\frac{p_2}{p_1} )=8.314\frac{J}{mol*K}*300K*ln(\frac{1000kPa}{100kPa} ) \\\\W_{isothermal}=5.743\frac{kJ}{mol}$

Regards.

8 0

3 years ago

6. Plants play a vital role in the environment because photosynthesis

Vanyuwa [196]

Answer:

C

Explanation:

Plants help in carbon dioxode reduction so plants uses atmospheric carbon dioxide and water to produce sugars and oxygen.

HOPE ITS HOPEFUL.

6 0

3 years ago

Read 2 more answers

a scientist finds an organism that has a single cell without a nucleus.This organism was found in pond water.In which KINGDOM do

notka56 [123]

Archaea (Archaeon ): Single-celled microorganisms without nuclei and with membranes different from all other organisms. Once thought to be bacteria.

Unicellular organism

-A unicellular organism, also known as a single-celled organism, is an organism that consists of a single cell, unlike a multicellular organism that consists of multiple cells. Unicellular organisms fall into two general categories: prokaryotic organisms and eukaryotic organisms.

8 0

3 years ago

Find the [H+] in an acetic acid solution that has a pH of 5.12

Eva8 [605]

Data:
pH = 5.2
[H+] = ?

Knowing that: (Equation to find the pH of a solution)
$pH = -log[H+]$

Solving:
 $pH = -log[H+]$
$5.2 = - log [H+]$
Knowing that the exponential is the opposite operation of the logarithm, then we have:
$[H+] = 10^{-5.2}$
$\boxed{\boxed{[H+] = 6.30*10^{-6}}}\end{array}}\qquad\quad\checkmark$

3 0

3 years ago

Place the following covalent bonds in order from least to most polar: a. H-Cl b. H-Br c. H-S d. H-C

timofeeve [1]

Answer:

The Order is as follow,

C-H < S-H < H-Br < H-Cl

Explanation:

Polarity depends on the electronegativity difference between two atoms, greater the electronegativity difference, greater will be the polarity of bond and vice versa.

Electronegativity Difference between Hydrogen and other given elements are as follow,

1) C-H;

E.N of Carbon = 2.55

E.N of Hydrogen = 2.20

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Difference 0.35

2) S-H;

E.N of Sulfur = 2.58

E.N of Hydrogen = 2.20

------------

Difference 0.38

3) H-Br;

E.N of Bromine = 2.96

E.N of Hydrogen = 2.20

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Difference 0.76

4) H-Cl;

E.N of Chlorine = 3.16

E.N of Hydrogen = 2.20

-----------

Difference 0.96

Hence it is proved that the greatest electronegativity difference is found between H and Chlorine in H-Cl, therefore it is highly polar bond and vice versa.

7 0

3 years ago