All categories

3 years ago

To accelerate, an object must *

Physics

1 answer:

Sonja [21]3 years ago

4 0

Answer: Not 100% sure but I think it’s C.

Hope this helps! ^^

You might be interested in

What happen to the frequency of transverse vibration of a stretched string if its tension is halved and the area of cross sectio

Stolb23 [73]

Answer:

The fundamental frequency of the stretched string is:

$f=$ $\frac{1}{2} \sqrt{\frac{T}{L} }$ [ T = Tension and μ = mass per unit length]

Here,

μ = $\frac{m}{L} = \frac{Vp}{L} = Ap$

$f= \frac{1}{2} \sqrt{\frac{T}{Ap} }$

If T is halved and A is doubled,

$f= \frac{1}{2} \sqrt{\frac{T'}{A'p} } = \sqrt{\frac{1}{2* 2* A* p} } = \frac{1}{2} (\frac{1}{2} \sqrt{\frac{T}{Ap} } = \frac{1}{2} f$

Thus, the frequency is reduced to half if its tension is halved and the area of cross-section of the string is doubled.

7 0

3 years ago

During a science fair, a group of students came up with the following question: “Is color an inherent property in objects or is

liraira [26]

I think the correct answer from the choices listed above is option B. The question that the group of students came up with would be an extremely difficult question to answer scientifically because how people see or experience color is subjective and people might see it differently.

3 0

3 years ago

Read 2 more answers

An electron is in motion at 4.0 × 106 m/s horizontally when it enters a region of space between two parallel plates, as shown, s

max2010maxim [7]

Answer:

xmax = 9.5cm

Explanation:

In this case, the trajectory described by the electron, when it enters in the region between the parallel plates, is a semi parabolic trajectory.

In order to find the horizontal distance traveled by the electron you first calculate the vertical acceleration of the electron.

You use the Newton second law and the electric force on the electron:

$F_e=qE=ma$ (1)

q: charge of the electron = 1.6*10^-19 C

m: mass of the electron = 9.1*10-31 kg

E: magnitude of the electric field = 4.0*10^2N/C

You solve the equation (1) for a:

$a=\frac{qE}{m}=\frac{(1.6*10^{-19}C)(4.0*10^2N/C)}{9.1*10^{-31}kg}=7.03*10^{13}\frac{m}{s^2}$

Next, you use the following formula for the maximum horizontal distance reached by an object, with semi parabolic motion at a height of d:

$x_{max}=v_o\sqrt{\frac{2d}{a}}$ (2)

Here, the height d is the distance between the plates d = 2.0cm = 0.02m

vo: initial velocity of the electron = 4.0*10^6m/s

You replace the values of the parameters in the equation (2):

$x_{max}=(4.0*10^6m/s)\sqrt{\frac{2(0.02m)}{7.03*10^{13}m/s^2}}\\\\x_{max}=0.095m=9.5cm$

The horizontal distance traveled by the electron is 9.5cm

4 0

4 years ago

NEED THIS NOW PLZ!!!

SVETLANKA909090 [29]

Answer: velocity

Explanation: Hope this helps :)

8 0

3 years ago

Which of the following atoms is least likely to form chemical bonds with other atoms

wariber [46]

The atom that would least likely form chemical bonds with other atoms would be C. A neon containing 4 valence electrons, this is because neon itself is an inert gas, it would not necessarily react as it already possess the maximum number of electrons needed to achieve stability and have a full octet, even if it is forced to obtain 4 valence electrons it would not react with other atoms.

8 0

3 years ago