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3 years ago

To accelerate, an object must *

Physics

1 answer:

Sonja [21]3 years ago

4 0

Answer: Not 100% sure but I think it’s C.

Hope this helps! ^^

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What is SI unit for distance

Dafna11 [192]

Answer:

meter

The SI unit of distance and displacement is the meter [m].

Explanation:

have advancedd

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3 years ago

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A car slams on its breaks,producing friction between the tires and the road.Into which type of energy is the mechanical energy o

Step2247 [10]

The answer is Heat Energy

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3 years ago

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Magnesium is a highly flammable element which is easily combustible in the presence of oxygen:

NemiM [27]

4 atoms

Explanation:

On the product side, we expect to find 4 atoms of the product.

An atom is the smallest indivisible particle that takes part in a chemical reaction.

An element is a distinct substance that cannot be split-up into simpler substances. Such substances consist of only one kind of atom.

In this reaction we have:

2 elements: Mg O

on the reactant side:

We have two moles of Mg: 2 atoms of Mg

1 mole of oxygen gas: 2 atoms of O

total atoms: 4 atoms

According to the law of conservation of matter "in a chemical reaction, matter is neither created nor destroyed".

We expect to find 4 atoms of products which is MgO on the product side.

2Mg + O₂ → 2MgO + heat

Learn more:

Conservation of matter brainly.com/question/2190120

#learnwithBrainly

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3 years ago

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The figure above shows 4forces 3N, 10N, 3√3N, and 6N acting on a particle P. The resultant of the four forces is.

Brilliant_brown [7]

As you gave no pic I took them on one lined

F_1=3N
F_2=10N
F_3=3root 3 N
F_4=6N

$\\ \sf\longmapsto F_{net}=F_1+F_2\dots$

$\\ \sf\longmapsto F_{net}=3+10+6+3\sqrt{3}$

$\\ \sf\longmapsto F_{net}=19+3(1.732)$

$\\ \sf\longmapsto F_{net}=19+5.196$

$\\ \sf\longmapsto F_{net}=24.196N$

6 0

3 years ago

Two objects each moving with speed v travel in opposite directions along a straight line passing through both their centers. The

Tpy6a [65]

Answer:

$\dfrac{1}{16}$

$\dfrac{5}{3}$

Explanation:

$m_1$ = Mass of first object

$m_2$ = Mass of second object

v = Speed of both objects

$\dfrac{v}{4}$ = Combined velocity

The ratio of final kinetic energy to initial kinetic energy will be

$\dfrac{K_f}{K_i}=\dfrac{\dfrac{1}{2}(m_1+m_2)(\dfrac{v}{4})^2}{\dfrac{1}{2}(m_1v^2+m_2v^2)} \\\Rightarrow \dfrac{K_f}{K_i}=\dfrac{(m_1+m_2)\dfrac{v^2}{16}}{m_1v^2+m_2v^2}\\\Rightarrow \dfrac{K_f}{K_i}=\dfrac{(m_1+m_2)\dfrac{1}{16}}{m_1+m_2}\\\Rightarrow \dfrac{K_f}{K_i}=\dfrac{1}{16}$

The ratio is $\dfrac{1}{16}$

As the linear momentum is conserved

$m_1v-m_2v=(m_1+m_2)\dfrac{v}{4}\\\Rightarrow m_1-m_2=(m_1+m_2)\dfrac{1}{4}$

Divide by $m_2$ on both sides

$\dfrac{m_1}{m_2}-1=\dfrac{m_1}{4m_2}+\dfrac{1}{4}\\\Rightarrow \dfrac{m_1}{m_2}-\dfrac{m_1}{4m_2}=\dfrac{1}{4}+1\\\Rightarrow \dfrac{3m_1}{4m_2}=\dfrac{5}{4}\\\Rightarrow \dfrac{m_1}{m_2}=\dfrac{5\times 4}{3\times 4}\\\Rightarrow \dfrac{m_1}{m_2}=\dfrac{5}{3}$

The ratio of mass is $\dfrac{5}{3}$

6 0

3 years ago