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Komok [63]
3 years ago
5

A car traveling with an initial velocity of 12 m/s accelerates at a constant rate of 2.2 m/s2 for a time of 4 seconds.

Physics
1 answer:
bazaltina [42]3 years ago
4 0
So what's the question?
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The average distance between the Sun and a certain planet is approximately 2.3 x 1014 inches. Which of the following is closest
Liono4ka [1.6K]

Answer:

B. 5.9 X 10^9

Explanation:

For this question, we assume the following:

•2.3 x 1014 inches is actually 2.3 x 10^14 inches.

•3.9 x 104inches is actually 3.9 x 10^4inches

We now calculate thus;

The average distance in km would be 2.3 x 10^14/3.9 x 10^4

= 0.59 X 10^10.

Therefore, we have;

5.9 X 10^9km.

8 0
3 years ago
The derived unit for pressure​
olga2289 [7]

Answer:

pascal

Explanation:

7 0
3 years ago
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PLEASE HELP!! <br><br> 6. What amount of force is needed to accelerate a 560kg bus at 1.4m/s??
Keith_Richards [23]

Answer:ugly nlikeieieisj

Explanation:ebebbebebebes

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3 years ago
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Imagine you have a collection of identical flat-bottomed coffee filters that can be nested (stacked inside of each other) so tha
skad [1K]

Answer:

the terminal velocity of 14 nested coffee filters is 3.2 m/s

Explanation:

Given the data in the question;

we know that;

The terminal velocity is proportional to the square root of weight.

v ∝ √W

v = k√W

the proportionality constant depends upon the surface area and the density of the medium (like air). The coffee filters can be stacked such that the resulting area is roughly unchanged. So, the constant of proportionality k is also unchanged

v/√W = constant

v₂/√W₂ = v₁/√W₁

v₂ = v₁√(W₂ / W₁ )

given that;

v₁ = 0.856 m/s,

W₂ = 14W₁; meaning 14 coffee filters have 14 times the weight of a single coffee filter

so we substitute

v₂ = 0.856 √(14W₁  / W₁ )

v₂  = 0.856 √( 14( W₁/W₁)

v₂  = 0.856 √( 14(1)

v₂  = 0.856 √( 14 )

v₂  = 0.856 × 3.741657

v₂  = 3.2 m/s

Therefore, the terminal velocity of 14 nested coffee filters is 3.2 m/s

6 0
3 years ago
The student soon loses his balance and falls backwards off the board at a velocity of 1.0 m/s. Assuming momentum is conserved in
Phantasy [73]

Answer:

v2 = 27.3m/s

Explanation:

Assuming forward as positive.

Mass = m1 = 64kg

Let v be the common velocity of the student and the skateboard.

mass of skateboard = m2 = 5.94kg

v = 1.4m/s

Since the skateboard and the student are initially moving together at the same velocity their momentum together is

(m1 + m2)v

Let the final velocity of the student be v1 and the final velocity of the skateboard be v2

v1 = – 1.0m/s (falls backwards that's why the velocity is negative since we are assuming forward as positive)

Then from conservation of momentum, momentum before is equal to momentum after.

(m1 + m2)v = m1v1 + m2v2

m2v2= (m1 + m2)v – m1v1

v2 = ( (m1 + m2)v – m1v1)/m2

v2 = ( (64 + 5.94)×1.4 – 64×(-1.0))/5.94

v2 = ( (64 + 5.94)×1.4 + 64×1.0)/5.94

v2 = 27.3m/s

5 0
3 years ago
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