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2 years ago

A hot rod can accelerate from 0 to 60 km/h in 5.4 s.

Physics

1 answer:

mylen [45]2 years ago

6 0

Answer:

<h2>a) Acceleration is 3.09 m/s²</h2><h2>b) Distance traveled is 45.05 m</h2><h2>c) Time taken to travel 250 m is 12.72 s</h2>

Explanation:

a) We have equation of motion v = u + at

Initial velocity, u = 0 km/hr = 0 m/s

Final velocity, v = 60 km/hr = 16.67 m/s

Time, t = 5.4 s

Substituting

v = u + at

16.67 = 0 + a x 5.4

a = 3.09 m/s²

Acceleration is 3.09 m/s²

b) We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 0 m/s

Acceleration, a = 3.09 m/s²

Time, t = 5.4 s

Substituting

s = ut + 0.5 at²

s = 0 x 5.4 + 0.5 x 3.09 x 5.4²

s = 45.05 m

Distance traveled is 45.05 m

c) We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 0 m/s

Acceleration, a = 3.09 m/s²

Displacement, s = 0.25 km = 250 m

Substituting

s = ut + 0.5 at²

250 = 0 x t + 0.5 x 3.09 xt²

t = 12.72 s

Time taken to travel 250 m is 12.72 s

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Given the thermochemical equations X2+3Y2⟶2XY3ΔH1=−370 kJ X2+2Z2⟶2XZ2ΔH2=−120 kJ 2Y2+Z2⟶2Y2ZΔH3=−270 kJ Calculate the change in

Alchen [17]

Answer : The change in enthalpy of the reaction is, -310 kJ

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given main reaction is,

$4XY_3+7Z_2\rightarrow 6Y_2Z+4XZ_2$ $\Delta H=?$

The intermediate balanced chemical reaction will be,

(1) $X_2+3Y_2\rightarrow 2XY_3$ $\Delta H_1=-370kJ$

(2) $X_2+2Z_2\rightarrow 2XZ_2$ $\Delta H_2=-120kJ$

(3) $2Y_2+Z_2\rightarrow 2Y_2Z$ $\Delta H_3=-270kJ$

Now we will reverse the reaction 1 and multiply reaction 1 by 2, reaction 2 by 2 and reaction 3 by 3 then adding all the equations, we get :

(1) $4XY_3\rightarrow 2X_2+6Y_2$ $\Delta H_1=2\times (+370kJ)=740kJ$

(2) $2X_2+4Z_2\rightarrow 4XZ_2$ $\Delta H_2=2\times (-120kJ)=-240kJ$

(3) $6Y_2+3Z_2\rightarrow 6Y_2Z$ $\Delta H_3=3\times (-270kJ)=-810kJ$

The expression for enthalpy of formation of $CH_4$ will be,

$\Delta H=\Delta H_1+\Delta H_2+\Delta H_3$

$\Delta H=(+740kJ)+(-240kJ)+(-810kJ)$

$\Delta H=-310kJ$

Therefore, the change in enthalpy of the reaction is, -310 kJ

5 0

3 years ago

What is the equivalent of 0° C in Kelvin?<br> Help will give brainiest

givi [52]

Answer:

273.15 dat is the answer im pretty sure

8 0

3 years ago

A laser with a power of 1.0 mW has a beam radius of 1.0 mm. What is the peak value of the electric field in that beam

Fynjy0 [20]

Answer:

The peak value of the electric field is 489.64 V/m

Explanation:

Given;

power of the laser, P = 1.0 mW = 1 x 10⁻³ W

Radius of the beam, R = 1.0 mm = 1 x 10⁻³ m

Area of the beam = πr² = π(1 x 10⁻³ )² = 3.142 x 10⁻⁶ m²

The average intensity of the light = P / A

The average intensity of the light = ( 1 x 10⁻³) / (3.142 x 10⁻⁶)

The average intensity of the light = 318.27 W/m²

The peak value of the electric field is given by;

$E_o = \sqrt{\frac{2I_{avg}}{c\epsilon_o}}\\\\E_o = \sqrt{\frac{2(318.27)}{(3*10^8)(8.85*10^{-12})}}\\\\E_o = 489.64 \ V/m$

Therefore, the peak value of the electric field is 489.64 V/m.

4 0

3 years ago

How much heat is required to heat 2 kg of water from 25°C to 40°C?

Dominik [7]

Answer:

126000 J

Explanation:

Applying,

Q = cm(t₂-t₁).................. Equation 1

Where Q = Amount of heat, c = specifc heat capacity of water, m = mass of water, t₁ = Initial temperature, t₂ = Final temperature.

From the question,

Given: m = 2 kg, t₁ = 25°C, t₂ = 40°C

Constant: c = 4200 J/kg.°C

Substitute these value into equation 1

Q = 2×4200(40-25)

Q = 2×4200×15

Q = 126000 J

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3 years ago

Which element of a valid contract is established by getting the signatures of all parties?

sweet [91]

The element of a valid contract which is established by getting the signatures of all parties is <u>mutual agreement</u>

<h3>What is an element of a valid contract?</h3>

An element of a valid contract simply refers to that promise made between two or more parties that which allow the courts to make judgement.

Some elements of valid contract are:

Offer
Acceptance
Consideration
Intention to create legal relation
Certainty and capacity.

So therefore, the element of a valid contract which is established by getting the signatures of all parties is mutual agreement

Learn more about elements of a valid contract:

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8 0

1 year ago