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weeeeeb [17]
2 years ago
10

A hot rod can accelerate from 0 to 60 km/h in 5.4 s.

Physics
1 answer:
mylen [45]2 years ago
6 0

Answer:

<h2>a) Acceleration is 3.09 m/s²</h2><h2>b) Distance traveled is 45.05 m</h2><h2>c) Time taken to travel 250 m is 12.72 s</h2>

Explanation:

a) We have equation of motion v = u + at

      Initial velocity, u = 0 km/hr = 0 m/s

      Final velocity, v = 60 km/hr = 16.67 m/s  

      Time, t = 5.4 s

      Substituting

                       v = u + at  

                       16.67 = 0 + a x 5.4

                       a = 3.09 m/s²

      Acceleration is 3.09 m/s²

b) We have equation of motion s = ut + 0.5 at²

         Initial velocity, u = 0 m/s

         Acceleration, a = 3.09 m/s²

         Time, t = 5.4 s      

      Substituting

                       s = ut + 0.5 at²

                       s = 0 x 5.4 + 0.5 x 3.09 x 5.4²

                       s = 45.05 m

       Distance traveled is 45.05 m

c) We have equation of motion s = ut + 0.5 at²

         Initial velocity, u = 0 m/s

         Acceleration, a = 3.09 m/s²

         Displacement, s = 0.25 km = 250 m      

      Substituting

                       s = ut + 0.5 at²

                       250 = 0 x t + 0.5 x 3.09 xt²

                       t = 12.72 s

       Time taken to travel 250 m is 12.72 s

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Answer:L=109.16 m

Explanation:

Given

initial temperature =20^{\circ}C

Final Temperature =80^{\circ}C

mass flow rate of cold fluid \dot{m_c}=1.2 kg/s

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Let final Temperature be T

mass flow rate of geothermal water \dot{m_h}=2 kg/s

diameter of inner wall d_i=1.5 cm

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specific heat of water c=4.18 kJ/kg-K

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A=\pi DL=5.144

L=\frac{5.144}{\pi \times 0.015}

L=109.16 m

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