Answer:
<h2>a)
Acceleration is 3.09 m/s²</h2><h2>
b) Distance traveled is 45.05 m</h2><h2>c)
Time taken to travel 250 m is 12.72 s</h2>
Explanation:
a) We have equation of motion v = u + at
Initial velocity, u = 0 km/hr = 0 m/s
Final velocity, v = 60 km/hr = 16.67 m/s
Time, t = 5.4 s
Substituting
v = u + at
16.67 = 0 + a x 5.4
a = 3.09 m/s²
Acceleration is 3.09 m/s²
b) We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 3.09 m/s²
Time, t = 5.4 s
Substituting
s = ut + 0.5 at²
s = 0 x 5.4 + 0.5 x 3.09 x 5.4²
s = 45.05 m
Distance traveled is 45.05 m
c) We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 3.09 m/s²
Displacement, s = 0.25 km = 250 m
Substituting
s = ut + 0.5 at²
250 = 0 x t + 0.5 x 3.09 xt²
t = 12.72 s
Time taken to travel 250 m is 12.72 s
