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Leviafan [203]
3 years ago
14

What differentiates the master builder approach prior to the Renaissance from later approaches? Projects do not depend on indivi

dual knowledge but leverage the total knowledge of the team. The engineering and construction roles dominated projects because architectural designs were so simple. The architect and engineer roles are clearly separated into separate project phases. Knowledge is confined to particular individuals and not shared or formalized into a recognizable set of standards.
Engineering
1 answer:
mr Goodwill [35]3 years ago
3 0

Answer:

Design-Build, though not new as a delivery method for building projects, appears to be on the rise. Traditionally known as the Master-Builder method, it is a means of building where one party holds responsibility for both the design and the construction. The Master-Builder method was the only method before the now ubiquitous design-bid-build project structure. The Romans for example, famous for their roads, aqueducts, and amphitheaters, did not design a project, bid it out to subcontractors, and then select the low bidder to build it, but rather designed and built structures in a collaborative, somewhat simultaneous fashion. In building a house for a client during Colonial times, one party, such as a master carpenter, was responsible for delivering the general layout and exterior details, selecting structural members, and completing construction. In this way, the carpenter acted as the architect, engineer, and builder simultaneously. The concept of design, bid, and build arose out of the natural specialization of the architect, engineer, and builder in the post-1850s world, where modern structural engineering was born and separated from architecture, and architects and builders fully separated as distinct and separate entities.

Explanation:

google

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A pipe leads from a storage tank on the roof of a building to the ground floor. The absolute pressure of the water in the storag
Fudgin [204]

Answer:

6.4 m/s

Explanation:

From the equation of continuity

A1V1=A2V2 where A1 and V1 are area and velocity of inlet respectively while A2 and V2 are the area and velocity of outlet respectively

A1=\pi (r1)^{2}

A2=\pi (r2)^{2}

where r1 and r2 are radius of inlet and outlet respectively

v1 is given as 1.6 m/s

Therefore

\pi (0.01)^{2}\times 1.6 = \pi (0.005)^{2}v2

V2=\frac {\pi (0.01)^{2}\times 1.6}{\pi (0.005)^{2}}=6.4 m/s

3 0
4 years ago
can you translate this me gusta el queso :sorry i would have put 300 points buut i used them all for my last question
Irina-Kira [14]
Translate in Spanish: lo siento, hubiera puesto 300 puntos pero los usé todos para mi última pregunta



If you meant a different language lmk
4 0
3 years ago
When we utilize a visualization on paper/screen, that visualization is limited to exploring: Group of answer choices Relationshi
Mila [183]

Answer:

As many variables as we can coherently communicate in 2 dimensions

Explanation:

Visualization is a descriptive analytical technique that enables people to see trends and dependencies of data with the aid of graphical information tools. Some of the examples of visualization techniques are pie charts, graphs, bar charts, maps, scatter plots, correlation matrices etc.

When we utilize a visualization on paper/screen, that visualization is limited to exploring as many variables as we can coherently communicate in 2-dimensions (2D).

6 0
3 years ago
Why do automotive technicians need to have good computer skills?​
Elden [556K]

Answer:

Just think about the number of computerized functions there are in modern automobiles.

Explanation:

8 0
3 years ago
If copper (which has a melting point of 1085°C) homogeneously nucleates at 849°C, calculate the critical radius given values of
____ [38]

Answer:

The critical radius is -1.30 nm

Explanation:

Temperature for homogenous nucleation of copper, T_{H} = 849^{0} C = 849 + 273 = 1122 K

Melting point of copper, T_{cu} = 1085^{0} C = 1085 + 273 = 1358 K

Latent heat of fusion, H_{f} = -1.77 * 10^{9} J/m^{3}

Surface free energy, \gamma = 0.200 J/m^{2}

Critical radius, r = ?

The formula for the critical radius is given by:

r = \frac{2 \gamma T_{cu} }{H_{f}(T_{cu} - T_{H})  }

r = \frac{2 * 0.2*1358 }{(-1.77 * 10^{9}) (1358 - 1122)  }

r = \frac{543.2 }{(-1.77 * 10^{9}) 236}\\r = -1.30 * 10^{-9} m\\r = -1.30 nm

The critical radius is -1.30 nm

8 0
4 years ago
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