<u>Answer:</u> The mass of sulfur dioxide gas at STP for given amount is 16.8 g
<u>Explanation:</u>
At STP conditions:
22.4 L of volume is occupied by 1 mole of a gas.
So, 5.9 L of volume will be occupied by = 
Now, to calculate the mass of a substance, we use the equation:

Moles of sulfur dioxide gas = 0.263 mol
Molar mass of sulfur dioxide gas = 64 g/mol
Putting values in above equation, we get:

Hence, the mass of sulfur dioxide gas at STP for given amount is 16.8 g
It should remain constant because of the law of conservation of mass and because the flask is sealed no mass will escape
The answer is 37.5 moles
The explanation:
1- when we have the mass of SO3 in Kg so, first we have to convert it to grams:
mass = 3 * 1000 = 3000 g
2- we need to get the molar mass of SO3 :
molar mass of SO3 = 32 + (16*3)
= 80 g/mol
3- then we can use this formula to get number of moles:
moles = mass / molar mass
= 3000 g / 80 g/mol
= 37.5 moles