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ipn [44]
3 years ago
11

How do longitudinal waves transport energy?

Physics
1 answer:
marissa [1.9K]3 years ago
6 0

A longitudinal wave transports energy through the medium without permanently transporting matter.


Hope this helps :D

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A metal rod is 25.000 cm long at 25.0 degrees Celsius. When heated to 102.0
ser-zykov [4K]

Answer:

The coefficient of linear expansion \alpha =2.8\times 10^-5\°C

Explanation:

Given initial temperature t_1=25°C

And final temperature t_2=102°C

Initial length l_1=25.000\ cm

Final length l_2=25.054\ cm

We have to find the coefficient of linear expansion

The coefficient of linear expansion is defined as the change in length per unit original length divide by the change in temperature.

l_2=l_1(1+\alpha (t_2-t_1))\\l_2-l_1=\alpha l_1(t_2-t_1)\\25.054-25.000=25.000(\alpha (102-25))\\0.054=\alpha\times 25(77)\\0.054=\alpha\times1925\\\alpha =\frac{0.054}{1925}=0.000028\C\\\alpha =2.8\times 10^-5

So, \alpha =2.8\times 10^-5\°C

4 0
3 years ago
A car moving 20 km/h skids 30 m with locked brakes. how far will the car skid with locked breaks if it were traveling at 100 km/
Inessa05 [86]

Kinetic energy = (1/2) (mass) (speed)²

Since the 'speed' in the KE formula is squared, if the car's speed
increases by 5 times, its kinetic energy increases by (5²) = 25 times.

The loss of kinetic energy in a skid is just the wo0rk done by friction
between the tires and pavement.  So the skid distance is proportional
to the initial kinetic energy, and the car must skid 25 times as far when
it enters the skid at the higher speed.

         25 x 30m  =  750 meters
5 0
4 years ago
A(n) 6.6 kg bowling ball is rolling towards the bowling pins. If its momentum is 15.9 kg*m/s, how fast is it traveling, in m/s?
Vedmedyk [2.9K]

Answer:

2.4m/s towards the bowling pins

Explanation:

Given parameters:

Mass of the ball  = 6.6kg

Momentum of the ball  = 15.9kgm/s

Unknown:

Speed of the ball  = ?

Solution:

The momentum is the amount of motion a body posses;

      Momentum = mas x velocity

Insert the parameters and solve;

      15.9  = 6.6 x velocity

        velocity  = 2.4m/s towards the bowling pins

3 0
3 years ago
(m = 4.0 kg) the cockroach rides on the rim (at radius R) of a disk (M = 6.0 kg) that turns about its center like a merry-go-rou
kvasek [131]

Answer:

ω' = 2.5 rad/s

Explanation:

mass of cockroach, m = 4 kg

mass of disk, M = 6 kg

Radius of disc= R

initial angular velocity, ω = 2 rad/s

Let the final angular velocity is ω'

As no external torque is applied, so the angular momentum is constant.

Angular momentum = Moment of inertia x angular velocity

I ω = I' ω'

\frac{1}{2}\left ( M+m \right )R^{2}\times {2} = \left (\frac{1}{2}MR^{2}+m(0.5R)^{2})  \right )\omega '

10R^{2} = 4R^{2}\omega '

ω' = 2.5 rad/s

5 0
4 years ago
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PtichkaEL [24]

Answer:

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Explanation:

6 0
3 years ago
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