Answer:
Given that
u = 13 m/s
h= 23 m
a) horizontally
We know that acceleration due top gravity is in vertical direction.
v²=u'²+ 2 g h ( u'= 0 )
v² = 2 x 9.81 x 23
v= 21.24 m/s ( vertical direction)
In the horizontal direction
u = 13 m/s
The resultant velocity
V²=v²+u²
V²=21.24²+13²
V= 24.91 m/s
(b) vertically straight up
u= 13 m/s
v²=u²+ 2 g h
v²=13²+ 2 x 9.81 x 23
v= 24.91 m./s
c)vertically straight down.
u= 13 m/s
v²=u²+ 2 g h
v²=13²+ 2 x 9.81 x 23
v= 24.91 m./s
There is no picture to reference from so I’m going to take a wild guess and say A
I think that the answer is A
Answer:
a. The station is rotating at
b. the rotation needed is
Explanation:
We know that the centripetal acceleration is
where is the rotational speed and r is the radius. As the centripetal acceleration is feel like an centrifugal acceleration in the rotating frame of reference (be careful, as the rotating frame of reference is <u>NOT INERTIAL,</u> the centrifugal force is a fictitious force, the real force is the centripetal).
<h3>a. </h3>
The rotational speed is :
Knowing that there are in a revolution and 60 seconds in a minute.
<h3>b. </h3>
The rotational speed needed is :
Knowing that there are in a revolution and 60 seconds in a minute.
4.372896 x 10^-7
Please give brainiest if possible