Answer:
177.8kJ/mol
Explanation:
In this reaction, the heat of decomposition is the same as the heat of formation. This is a decomposition reaction.
Given parameters:
ΔHf CaCO₃ = -1206.9kJ/mol
ΔHf CaO = −635.6 kJ/mol
ΔHf CO₂ = −393.5 kJ/mol
The heat of decomposition =
Sum of ΔHf of products - Sum of ΔHf of reactants
The equation of the reaction is shown below:
CaCO₃ → CaO + CO₂
The heat of decomposition = [ -635.6 + (-393.5)] - [−1206.9 ]
= -1029.1 + 1206.9
= 177.8kJ/mol
<span>number Moles of C = 54.5 g / 12.011 = 4.54
number Moles of H = 9.10 / 1.008 = 9.02
number Moles of O = 36.4 / 16 = 2.28
if we want to divide by the smallest number
4.54 / 2.28 = 2 => C
9.02 / 2.28 = 4 => H
2.28 / 2.28 = 1 => O
Empirical formula will be = C2H4O</span>
Answer:
C.) Argon
Explanation:
This is because ionisation energy increases as we move from left to right in a period. Argon presents in the right most column and Argon is a novel gas and has 8 electrons in outermost orbital. So, it is highly stable. I hope I helped! ^-^
Yes they are what are your options