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2 years ago

Explain how to properly engage the safety latches on the Stan Design Pit Jack.

Engineering

1 answer:

sattari [20]2 years ago

8 0

The way to properly engage the safety latches on the Stan Design Pit Jack is:

Connect the hydraulic jack.
Make sure it is properly lubricated.
Ensure that the rolling bridge jack is well fused together.
Use the machine.

<h3>What is the Stan Design Pit Jack?</h3>

This refers to the machination which makes use of pit jacks to execute tire rotation in a fast lube pit.

We can note that based on the design, this machine is put in the pit of a car and then rolls back and forth and perform their operations on both the front and real axles.

Hence, it is important to note that the safety latches are designed to prevent work accidents and it is important to properly lubricate the parts to prevent damage.

Read more about safety latches here:
brainly.com/question/24573204

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Applying the Entropy Balance: Closed Systems Five kg of carbon dioxide (CO2) gas undergoes a process in a well-insulated piston–

Mrrafil [7]

Answer:

a) the amount of energy produced in kJ/K is 0.73145 kJ/K

b) the amount of energy produced in kJ/K is 0.68975 kJ/K

The value for entropy production obtained using constant specific heats is approximately 6% higher than the value obtained when accounting explicitly for the variation in specific heats.

Explanation:

Draw the T-s diagram.

$C_p$ = 0.939 kJ/kg.K , m = 5 kg , T₂ = 520 K , T₁ = 280

R = [8.314 kJ / 44.01 kg.K] , P₂ = 20 bar , P₁ = 2 bar

Δs = $m[c_p ln(\frac{T_2}{T_1}) - Rln(\frac{P_2}{P_1})]$

Substitute all parameters in the equation

Δs = $5[(0.939) ln(\frac{520}{280}) - (\frac{8.314}{44.01})ln(\frac{20}{2})]$

Δs = 5 kg × 0.14629 kJ/kg.K

= 0.73145 kJ/K

Δs = $m[\frac{s^0(T_2) - s^0(T_1)}{M} - Rln(\frac{P_2}{P_1})]$

Where T₁ = 280 K , s°(T₁) = 211.376 kJ/kmol.K

T₂ = 520 K , s°(T₂) = 236.575 kJ/kmol.K

R = [8.314 kJ / 44.01 kg.K] , M = 44.01 kg.K , P₂ = 20 bar , P₁ = 2 bar

Δs = $5[\frac{236.575 - 211.376}{44.01} - (\frac{8.314}{44.01})ln(\frac{20}{2})]$

= 5 kg (0.13795 kJ/kg.K)

= 0.68975 kJ/K

The value for entropy production obtained using constant specific heats is approximately 6% higher than the value obtained when accounting explicitly for the variation in specific heats.

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4 years ago

The modifications of superheat and reheat for a vapor power plant are specifically better for the operation which of the followi

MatroZZZ [7]

The modifications of superheating and reheat for a vapor power plant are specifically better for the operation which of the following components b.Boiler.

<h3>What are the primary additives in the vapour strength cycle?</h3>

There are 5 steam strength cycles: The Carnot cycle, the easy Rankine cycle, the Rankine superheat cycle, the Rankine reheat cycle and the regenerative cycle.

Central to expertise the operation of steam propulsion is the primary steam cycle, a method wherein we generate steam in a boiler, increase the steam via a turbine to extract work, condense the steam into water, and sooner or later feed the water again to the boiler.
Reheat now no longer best correctly decreased the penalty of the latent warmness of vaporization in steam discharged from the low-stress quit of the turbine cycle, however, it additionally advanced the first-rate of the steam on the low-stress quit of the mills via way of means of decreasing condensation and the formation of water droplets inside the turbine.

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2 years ago

Suppose you were doing an A* search and there were a number of different ways that you could compute an admissible heuristic val

Elodia [21]

Answer:

Explanation:

First of all,we need to know what kind of research and how important it is before determining which computation method to use .

Then compare end result of research and cost of expensive methods .

Then we should opt for the best expensive method to be used for the given application.

5 0

3 years ago

Your program must output each student’s name in the form: last name followed by a comma, followed by a space, followed by the fi

Reptile [31]

Answer:

#include <iostream>

#include <string>

#include <fstream>

using namespace std;

char getStudentGrade(int testScore);

//Declare constant max students in file 10

const int maxStudents = 10;

struct StudentType

{

string studentFName;

string studentLName;

int testScore;

char grade;

};

void readStudentData(StudentType students[]){

int i = 0;

ifstream infile;

infile.open("inputStudentData.txt");

while (!infile.eof())

{

infile >> students[i].studentFName;

infile >> students[i].studentLName;

infile >> students[i].testScore;

students[i].grade = getStudentGrade(students[i].testScore);

i++;

}

char getStudentGrade(int testScore){

char grade;

if(testScore >= 80) {

grade = 'A';

}

else if(testScore >= 60) {

grade = 'B';

}

else if(testScore >= 50) {

grade = 'C';

}

else if(testScore >= 40) {

grade = 'D';

}

else {

grade = 'F';

}

return grade;

}

int main()

{

StudentType students[10];

readStudentData(students);

for(int i=0;i<maxStudents;i++) {

students[i].grade = getStudentGrade(students[i].testScore);

}

for(int i=0; i<maxStudents; i++){

cout << students[i].studentLName <<", " << students[i].studentFName << " " << students[i].grade << endl;

}

ofstream outputFile;

outputFile.open ("outputStudentData.txt");

for(int i=0; i<maxStudents; i++){

outputFile << students[i].studentLName <<", " << students[i].studentFName << " " << students[i].grade << endl;

}

outputFile.close();

return 0;

}

3 0

3 years ago

When brazing, the lowest effective brazing temperatures possible should be used to minimize the effects of heat on the base meta

nordsb [41]

Answer:

False

Explanation:

5 0

3 years ago