A. Testing a hypothesis
This leads to the other points
Answer:
halogen is the name of group 17 on the table of elements
Answer:
Ag₂CrO₄(s) + H⁺(aq) ⟶ 2Ag⁺(aq) + HCrO₄⁻(aq)
Explanation:
Ag₂CrO₄(s) ⇌ 2Ag⁺(aq) + CrO₄²⁻(aq).
Silver chromate is the salt of a strong base (AgOH) and a weak acid (H₂CrO₄).
HCrO₄⁻ is an even weaker acid than H₂CrO₄, so CrO₄²⁻ is a strong base.
Any added H⁺ will immediately combine with the chromate ions according to the reaction
H⁺ + CrO₄²⁻ ⟶ HCrO₄⁻
thereby removing chromate ions from solution.
According to Le Châtelier's Principle, more silver chromate will dissolve to replace the chromate ions that the H⁺ removes.
The overall equation for the reaction is
Ag₂CrO₄(s) ⇌ 2Ag⁺(aq) + <em>CrO₄²⁻(aq)
</em>
<u>H⁺(aq) + </u><em><u>CrO₄²⁻(aq)</u></em><u> ⟶ HCrO₄⁻(aq)
</u>
Ag₂CrO₄(s) + H⁺(aq) ⟶ 2Ag⁺(aq) + HCrO₄⁻(aq)
Answer:
A
Explanation:
When a reaction happens some of the reactants mass is released as energy so the mass of the product would be less
Answer:
Mass = 16.4 g
Explanation:
Given data:
Mass of K = 8.50 g
Mass of KCl produced = ?
Solution:
Chemical equation:
2K + Cl₂ → 2KCl
Number of moles of K:
Number of moles = mass/ molar mass
Number of moles = 8.50 g/ 39 g/mol
Number of moles = 0.22 mol
Now we will compare the moles of potassium and potassium chloride.
K : KCl
2 : 2
0.22 : 0.22
Mass of KCl:
Mass = number of moles × molar mass
Mass = 0.22 mol × 74.55 g/mol
Mass = 16.4 g