(3.500 mol MgO)(40.3044g MgO/1mol MgO)
=141.0654
Answer:
Could you provide a diagram?
Explanation:
Answer:
24%
Explanation:
From the question, the limiting reactant is H2S.
The reaction equation is;
2H2S + O2 → 2S + 2H2O
Number of moles of H2S reacted = 22g/34 g/mol = 0.647 moles
According to the reaction equation;
2 moles of H2S yields 2 moles of sulphur
0.647 moles of H2S yields 0.647 moles of sulphur
So;
Theoretical yield of sulphur = 0.647 moles * 32 g/mol = 20.7 g
Actual yield = 5 g
% yield = actual yield/theoretical yield * 100
% yield =5 g/20.7 g * 100
% yield = 24%
Answer: C6H6
Explanation: Molecular Formula is the molecular mass divided by the empirical formula mass of CH which is C 12and H is 1 so 12 + 1= 13 g CH
Solution:
78.11 g CH / 13 g CH = 6
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