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3 years ago

If the absolute temperature of a gas is tripled, what happens to the root‑mean‑square speed of the molecules?

Chemistry

1 answer:

Gnesinka [82]3 years ago

4 0

Answer:

D. The new rms speed is 1.732 times the original rms speed.

Explanation:

The expression for the root mean square speed is:

$C_{rms}=\sqrt {\dfrac {3RT}{M}}$

R is Gas constant having value = 8.314 J / K mol

M is the molar mass of gas

T is the absolute temperature

As seen from the formula, root mean square speed is directly proportional to the square root of the absolute temperature.

So,

$C_{rms}\propto \sqrt {T}$

Given, absolute temperature of a gas is tripled, so, the new rms speed will be √3 (1.732) of the original.

Hence, the correct option is:- D. The new rms speed is 1.732 times the original rms speed.

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How much carbon dioxide will be formed if 12.5 grams of oxygen reacts with 7.2 grams of propane (C3H8 )? Balanced equation: C3H8

solong [7]

Answer:

10.3125 grams of carbon dioxide will be formed.

Explanation:

The balanced reaction is:

C₃H₈ + 5 O₂→ 3 CO₂ + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles participate in the reaction:

C₃H₈: 1 mole
O₂: 5 moles
CO₂: 3 moles
H₂O: 4 moles

Being the molar mass of the compounds:

C₃H₈: 44 g/mole
O₂: 32 g/mole
CO₂: 44 g/mole
H₂O: 18 g/mole

then by stoichiometry of the reaction, the following amounts of mass participate in the reaction:

C₃H₈: 1 mole* 44 g/mole = 44 g
O₂: 5 moles* 32 g/mole= 160 g
CO₂: 3 moles* 44 g/mole= 132 g
H₂O: 4 moles* 18 g/mole= 72 g

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: If by reaction stoichiometry 44 grams of propane react with 160 grams of oxygen, 7.2 grams of propane react with how much mass of oxygen?

$mass of oxygen=\frac{7.2 grams of propane*160 grams of oxygen}{44 grams of propane}$

mass of oxygen= 26.18 grams

But 26.18 moles of O₂ are not available, 12.5 grams are available. Since you have less mass than you need to react with 7.2 grams of propane, oxygen O₂ will be the limiting reagent.

Then you can apply the following rule of three: if by stoichiometry of the reaction 160 grams of oxygen form 132 grams of carbon dioxide, 12.5 grams of oxygen will form how much mass of carbon dioxide?

$mass of carbon dioxide=\frac{12.5 grams of oxygen*132 grams of carbon dioxide}{160 grams of oxygen}$

mass of carbon dioxide= 10.3125 grams

10.3125 grams of carbon dioxide will be formed.

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3 years ago

3 reasons why aluminium is used in making of cooking vessels

Annette [7]

Answer is : It is a good thermal and electrical conductor. -The main point to be noted is that aluminium is a highly reactive element and still it is used for making cooking utensils. The reason is that aluminium has a very high affinity for oxygen. So, it reacts with oxygen and forms a layer of aluminium oxide on its surface.

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GuDViN [60]

Answer:

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Explanation:

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