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Alik [6]
3 years ago
11

Ight of a Prism Given the Base Area and

Physics
1 answer:
babunello [35]3 years ago
5 0

Answer:

Remember that V = Bh, so V = 120 * 5 = 600 ft³

Explanation:

You might be interested in
An ideal gas is confined to a container with constant volume. The number of moles is constant. By what factor will the pressure
Andrews [41]

Answer:

1/3

Explanation:

Gay Lusaac's law states that "the pressure of a given mass of gas is directly proportional with the absolute temperature of the gas, provided that the volume is kept constant."

In formula, we say that

P/T = k

Where

P = pressure at different points

T = temperature at different points

k = constant of proportionality

From the stated formula, if we multiply the temperature by 3, we have

P/3T = k

P * 1/3T = k

And from this, we see the pressure will change by a value of 1/3

4 0
3 years ago
What is the simplest relationship between the angular wavenumber k and just one of the other kinematic variables?
Inessa [10]

Answer : k=\dfrac{\omega}{k}

Explanation :

The word kinematics means the study of motion. Kinematic variables gives the description of the motion of the body.

Displacement, Velocity, acceleration and time are associated with the motion of particle.

Wavenumber is defined as the frequency of wave, which is measured in cycles per unit distance.

Wave number is also defines as:

k=\dfrac{2\pi}{\lambda}

where, \lambda is wavelength

k=\dfrac{2\pi}{\lambda}\times \dfrac{T}{T}

since, \dfrac{2\pi}{T}=\omega \ and\ \dfrac{1}{V}=\dfrac{T}{\lambda}

So, k=\dfrac{\omega}{V}

Where, \omega is angular frequency and V is velocity of wave.

Hence, the  relationship between the angular wavenumber k and and kinamatic variable V is

k=\dfrac{\omega}{V}

6 0
4 years ago
_____ developed the universal law of gravitation.
Sati [7]

Answer: Newton

Explanation:

8 0
4 years ago
Read 2 more answers
Write the type of energy present in pond water and kerosene?​
vichka [17]
Potential and kinetic energy
3 0
3 years ago
A box at rest has the shape of a cube 3.5 m on a side. This box is loaded onto the flat floor of a spaceship and the spaceship t
guapka [62]

Answer:

V_o=25.725\ m^3

Explanation:

Given:

sides of the cube, a=3.5\ m

speed of the cube with respect to the observer, v=0.8c

Since the relative velocity of the object is relativistic, so there will be a length contraction according to the observer:

a_o=a\div\frac{1}{\sqrt{1-\frac{v^2}{c^2} } }

where:

a_o= observed length of the side along the direction of velocity

a_o=3.5\div\frac{1}{\sqrt{1-\frac{(0.8c)^2}{c^2} } }

a_o=2.1\ m is the observed length of the cube edge only in the direction of the velocity due to relativistic effect of length contraction.

So the observed volume will be:

V_o=a\times a\times a_o

V_o=3.5\times 3.5\times 2.1

V_o=25.725\ m^3

5 0
3 years ago
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