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4 years ago

5. A 70 kg astronaut floating in an orbiting space station throws a 1.0 kg water bottle across the room at a

Physics

1 answer:

irina1246 [14]4 years ago

3 0

The recoil velocity of the astronaut is -0.11 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, in absence of external forces, the total momentum of the astronaut+water bottle is conserved.

Before the astronaut throws the bottle, the total momentum is zero:

p = 0 (1)

After throwing it, the total momentum is:

$p=mv+MV$ (2)

Where

m = 1.0 kg is the mass of the water bottle

v = 8.0 m/s is the velocity of the water bottle

M = 70 kg is the mass of the astronaut

V is the recoil velocity of the astronaut

Since the total momentum is conserved, (1) = (2), so we can write:

$0=mv+MV$

And solving for V, we find:

$V=-\frac{mv}{M}=-\frac{(1.0)(8.0)}{70}=-0.11 m/s$

where the negative sign indicates that the direction is opposite tot he direction of the water bottle.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

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