All categories

4 years ago

5. A 70 kg astronaut floating in an orbiting space station throws a 1.0 kg water bottle across the room at a

Physics

1 answer:

irina1246 [14]4 years ago

3 0

The recoil velocity of the astronaut is -0.11 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, in absence of external forces, the total momentum of the astronaut+water bottle is conserved.

Before the astronaut throws the bottle, the total momentum is zero:

p = 0 (1)

After throwing it, the total momentum is:

$p=mv+MV$ (2)

Where

m = 1.0 kg is the mass of the water bottle

v = 8.0 m/s is the velocity of the water bottle

M = 70 kg is the mass of the astronaut

V is the recoil velocity of the astronaut

Since the total momentum is conserved, (1) = (2), so we can write:

$0=mv+MV$

And solving for V, we find:

$V=-\frac{mv}{M}=-\frac{(1.0)(8.0)}{70}=-0.11 m/s$

where the negative sign indicates that the direction is opposite tot he direction of the water bottle.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

You might be interested in

The planet Mars has much less gravitational force that Earth. What would happen if you went to Mars?

vovangra [49]

gravitational force of planet exerted on its object near the surface is known as weight

so here we know that gravitational force of mars is much less than the gravitational force of Earth

So on the surface of mars the Weight of objects must be much less than the weight of object on surface of Earth

so here correct answer must be

D. Your weight would decrease.

6 0

4 years ago

Please help me with this question guys.

katen-ka-za [31]

Answer:

The average speed is 22.2 km/h

Explanation:

Average Speed

Given an object travels a total distance d and took a total time t, then the average speed is:

$\displaystyle \bar v=\frac{d}{t}$

The mailman first drives d1=7 km at v1=15 km/h. The time taken to drive is:

$\displaystyle t1=\frac{d1}{v1}=\frac{7}{15}=0.467\ h$

Then he drives d2=7 km at v2=43 km/h taking a time of:

$\displaystyle t2=\frac{d2}{v2}=\frac{7}{43}=0.163\ h$

The total time is

t=0.467 h + 0.163 h = 0.63 h

The total distance is

d = 7 km + 7 km = 14 km

The average speed is:

$\displaystyle \bar v=\frac{14}{0.63}=22.2\ km/h$

The average speed is 22.2 km/h

7 0

3 years ago

Is -3 a solution to equation 3x -5 = 4+ 2x

Elodia [21]

Answer:

No!

Explanation:

The correct answer is x = 9.

5 0

3 years ago

A solid weighs 200N in air, 150N in water and 170N in a liquid. Find relative density of solid, relative density of liquid and d

fomenos

Answer:

$\rho_{s} = 4$

$\rho_{l} = 0.6$

$\rho{liq} = 600 kg/m^{3}$

Given:

Weight of solid in air, $w_{sa} = 200 N$

Weight of solid in water, $w_{sw} = 150 N$

Weight of solid in liquid, $w_{sl} = 170 N$

Solution:

Calculation of:

1. Relative density of solid, $\rho_{s}$

$\rho_{s} = \frac{w_{sa}}{w_{sa} - w_{sw}}$

$\rho_{s} = \frac{200}{200 - 150} = 4$

2. Relative density of liquid, $\rho_{l}$

$\rho_{l} = \frac{w_{sa} - w_{sl}}{w_{sa} - w_{sw}}$

$\rho_{l} = \frac{200 - 170}{200 - 150} = 0.6$

3. Density of liquid in S.I units:

Also, we know:

$\rho{l} = \frac{\rho_{liq}}{\rho_{w}}$

where

$= {\rho_{liq}}$ = density of liquid

$= {\rho_{w}} = 1000 kg/m^{3}$ = density of water

Now, from the above formula:

$0.6 = \frac{\rho_{liq}}{1000}$

$\rho{liq} = 600 kg/m^{3}$

3 0

3 years ago

- The Grayprational Force with which the earth aracts а,

Fudgin [204]

Answer:

gravitational?

Explanation:

5 0

3 years ago