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OverLord2011 [107]
4 years ago
6

What are two features used to describe matter

Chemistry
2 answers:
wariber [46]4 years ago
7 0
Mass and weight are two features used to describe matter
laiz [17]4 years ago
5 0
The two factors used to describe matter are mass and weight
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A fixed, single pulley that is used to lift a block does which one of the following?
olga55 [171]
The answer is C, it makes the block easier to lift by changing the direction of the force needed to lift it 
4 0
3 years ago
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When 2.85 moles of chlorine reacts with excess tin, how many moles of tin(IV) chloride are formed
svp [43]
                                Sn + 2Cl2 ------> SnCl4
from reaction                2 mol            1 mol
from the problem          2.85 mol       x mol

x=2.85*1/2≈1.43 mol SnCl4
7 0
4 years ago
A 50.00-g sample of metal at 78.0°C is dropped into cold water. If the metal sample cools to 17.0°C and the specific heat of met
Luba_88 [7]

Answer:−329.4 calorie

Explanation:Heat released by metal = q=m_mc_m(T_2-T1)q=m

m

​

c

m

​

(T

2

​

−T1)

m_m=50\ g\\c_m=0.108\ cal\ g^{-1}\ \degree C^{-1}\\q=50\times0.108(17-78)=-329.4\ caloriem

m

​

=50 g

c

m

​

=0.108 cal g

−1

 °C

−1

q=50×0.108(17−78)=−329.4 calorie

Here minus sign indicate that heat is released

5 0
4 years ago
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Explain why it is not a good idea to throw an arsenal canon to fire. Which gas law applies?
Feliz [49]

Answer:

is a class of heavy military ranged weapons built to launch munitions far beyond the range and power of infantry firearms. This development continues today; modern self-propelled artillery vehicles are highly mobile weapons of great versatility generally providing the largest share of an army's total firepower.

Explanation:

it could explode

6 0
3 years ago
How many moles of dinitrogen tetroxide (N2O4) are in 6.49 x 109 particles?
yan [13]

Answer: There are 1.08 \times 10^{-14} moles N_{2}O_{4} present in 6.49 \times 10^9 particles.

Explanation:

According to the mole concept, 1 mole of a substance contains 6.022 \times 10^{23} particles.

Hence, number of moles present in 6.49 \times 10^9 particles are calculated as follows.

No. of moles = \frac{6.49 \times 10^9}{6.022 \times 10^{23}} mol

                      = 1.08 \times 10^{-14} mol

Thus, there are 1.08 \times 10^{-14} moles N_{2}O_{4} present in 6.49 \times 10^9 particles.

6 0
3 years ago
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