A combustion reaction of an will generally produce CO2 and H20 -- carbon dioxide and water and/or an oxide
looking at the combustion material C2H2, you know that the end products will be CO2 and H20, so the question is how much of each will you get
well, look at the total amount of carbon atoms, 2 C2, which means a total of 4 carbon atoms in this reaction, since only CO2 has carbon atoms, that means there must be 4 CO2 as an end product and 4 CO2 will use up 4 of 5 O2 molecule leaving only 1 O2 molecule for the H2 reaction.
now O2 has a total of 2 oxygen molecules whereas H20 has only a single oxygen molecule, hence the end product must have 2 H20
check that the H atoms balance out on both sides
Answer:
Na is the element from the second period that has the largest atomic radius
Explanation:
The atomic radius is a chemist property from the periodic table. It is decreased when we move in a period from the periodic, so the element in the second period that has the largest radius is Na, and the shortest, the Ar
The atomic radius indicates the distance between the nucleus and the outermost valence layer. In the periods it decreases with increasing Atomic Number, to the right, due to the attraction that the nucleus exerts on the electrons of the outermost orbitals, thus decreasing the core-electron distance.
Answer:
K = 4.07x10⁻³
Explanation:
Based on the reaction:
NH₄I(s) ⇄ NH₃(g) + HI(g)
You can define K of equilibrium as the ratio of concentrations of reactants and products, thus:
K = [NH₃] [HI] / [NH₄I]
But, as NH₄I is a solid, is not taken into account in the equilibrium, that means K expression is:
K = [NH₃] [HI]
As the concentrations in equilibrium of the gases is:
[NH₃] = 4.34x10⁻²M
[HI] = 9.39x10⁻²M
Equilibrium constant, K, is:
K = 4.34x10⁻²M * 9.39x10⁻²M
<h3>K = 4.07x10⁻³</h3>
