A car travels 150 meters in 3.5 seconds what is its speed?
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The value of x in CuSO4. xH2O is 5.
Given that;
Number of moles of anhydrous salt = Number of moles of hydrated salt
Number of moles of anhydrous salt = 319 ×
Mass of hydrated salt = 499 × g
Number of moles of anhydrous salt = 319 g/160 g/mol = 0.00199 moles
Number of moles of hydrated salt = 499 × g/ 160 + 18x
0.00199 = 499 × g/ 160 + 18x
0.00199 (160 + 18x) = 499 ×
0.318 + 0.036x = 0.499
0.036x = 0.499 - 0.318
0.036x = 0.181
x = 0.181/0.036
x = 5
Hence, x in CuSO4. xH2O is 5.
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The reaction of benzene with an alkyl chloride and aluminum trichloride is called a Friedel-Crafts alkylation. The aluminum trichloride is a lewis acid that reacts with the alkyl chloride, and this converts the alkyl group into a very good electrophile. The overall reaction is an electrophilic aromatic substitution. A pi bond of the benzene ring will attack the electrophile as a nucleophile and form a new carbon-carbon bond. The result is a monosubstituted isopropyl group on the benzene ring.
However, we are told that the conditions are set up to encourage dialkylation. The isopropyl group is a group that donates electron density through induction. Therefore, it is an ortho- and para-directing group. This means that once one isopropyl group is substituted on to the benzene ring, the second substitution will be favoured in the ortho- and para-positions. In this instance, the major product is the 1,4-disubstituted product. The reason being is that the isopropyl groups are very bulky, and the steric hindrance of having two isopropyl groups adjacent leads to a small amount of this product being formed.
There will also be trace amounts of the meta-substituted product, but the 1,4- and 1,2-substituted products are more favoured.
However, we are told that the conditions are set up to encourage dialkylation. The isopropyl group is a group that donates electron density through induction. Therefore, it is an ortho- and para-directing group. This means that once one isopropyl group is substituted on to the benzene ring, the second substitution will be favoured in the ortho- and para-positions. In this instance, the major product is the 1,4-disubstituted product. The reason being is that the isopropyl groups are very bulky, and the steric hindrance of having two isopropyl groups adjacent leads to a small amount of this product being formed.
There will also be trace amounts of the meta-substituted product, but the 1,4- and 1,2-substituted products are more favoured.