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bogdanovich [222]
3 years ago
8

When placed in a freezer , liquid water turns into ice . What best describes this change ?

Chemistry
2 answers:
My name is Ann [436]3 years ago
5 0
This is a physical change
GREYUIT [131]3 years ago
4 0

Answer:

Freezing

Explanation:

liquid changing to a solid = Freezing

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Which of the following work mostly severaly affect a human population
Arada [10]
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6 0
3 years ago
Phosphoric acid, which is commonly used as rust inhibitor, food additive and etching agent for dental and orthopedic use, can be
Sphinxa [80]

Answer:

P_4_{(I)}+5O_2_{(g)}+6H_2O_{(l)}\rightarrow +4H_3PO_4_{(l)}

Explanation:

The first step is:

P_4_{(I)}+5O_2_{(g)}\rightarrow 2P_2O_5_{(g)}

Second step is:

P_2O_5_{(g)}+3H_2O_{(l)}\rightarrow 2H_3PO_4_{(l)}

Multiplying second step by 2, and adding both the steps, we get that:

P_4_{(I)}+5O_2_{(g)}+2P_2O_5_{(g)}+6H_2O_{(l)}\rightarrow 2P_2O_5_{(g)}+4H_3PO_4_{(l)}

Cancelling common species, we get that:

P_4_{(l)}+5O_2_{(g)}+6H_2O_{(l)}\rightarrow +4H_3PO_4_{(l)}

6 0
3 years ago
what happens to the radius of the atoms of an element as you go towards the right in a row of the periodic table ?
Olegator [25]

Answer:

It decreases

Explanation:

As one moves from left to right on the periodic table, the radius of atoms reduces due to the nuclear pull.

  • The size of an atom estimated by the atomic radius is taken as half of the internuclear distance between the two covalently bonded atoms of non-metallic elements.
  • Across a period, atomic radius decreases progressively from left to right.
  • This is due to the increasing nuclear charge without attendant increase in the number of electronic shell.
7 0
3 years ago
What is the first step when factoring the trinomial ax^2+bx+c
dlinn [17]
This is all no chemistry but the answer is C
7 0
3 years ago
4.45 kcal of heat was added to increase the temperature of a sample of water from 23.0 °C to 57.8 °C. Calculate
Alona [7]

Answer:

m = 4450 g

Explanation:

Given data:

Amount of heat added = 4.45 Kcal ( 4.45 kcal ×1000 cal/ 1kcal = 4450 cal)

Initial temperature = 23.0°C

Final temperature = 57.8°C

Specific heat capacity of water = 1 cal/g.°C

Mass of water in gram = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 57.8°C - 23.0°C

ΔT = 34.8°C

4450 cal = m × 1 cal/g.°C × 34.8°C

m = 4450 cal / 1 cal/g

m = 4450 g

4 0
3 years ago
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