Question

500 g of water at 90°C is cooled in a freezer. If all the water is converted to ice, what is the amount of heat released when the water is cooled to a temperature of 0°C and becomes ice?
[Specific heat capacity of water = 4200 J kg^-1 °C^-1, specific latent heat of fusion of ice = 3.34 × 10^5 J kg^-1]


*can u show me how u get the answer? the answer must be 356000 J​

Answer 1

Answer:

356 000 J

Explanation:

Total Energy released

= Energy released when water cools to 0 + Energy released when water is converted to ice at 0

= mcT + ml

= (0.5)(4200)(90-0) + (0.5)(334 000)

= 189 000 J + 167 000 J

= 356 000 J