Answer:
a) the magnitude of the force is
F= Q(
) and where k = 1/4πε₀
F = Qqs/4πε₀r³
b) the magnitude of the torque on the dipole
τ = Qqs/4πε₀r²
Explanation:
from coulomb's law
E = 
where k = 1/4πε₀
the expression of the electric field due to dipole at a distance r is
E(r) = 
, where p = q × s
E(r) = 
where r>>s
a) find the magnitude of force due to the dipole
F=QE
F= Q()
where k = 1/4πε₀
F = Qqs/4πε₀r³
b) b) magnitude of the torque(τ) on the dipole is dependent on the perpendicular forces
τ = F sinθ × s
θ = 90°
note: sin90° = 1
τ = F × r
recall F = Qqs/4πε₀r³
∴ τ = (Qqs/4πε₀r³) × r
τ = Qqs/4πε₀r²
Gravity lets all objects fall to the ground at the same speed, 9.8 m/s/s. If the force of gravity were stronger, such as 10 m/s/s, the rate of acceleration would be faster.
Which conditions I think you have place an incorrect image?
Answer:
Large above ground mausoleums were not common in the elite Shang burials.
Explanation:
Large, above the ground mausoleums were not common so the answer is option B.
Answer: a) The rate constant, k, for this reaction is 
b) No 
does not depend on concentration.
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
Given: Order with respect to 
= 1
Thus rate law is:
a) ![Rate=k[A]^1](https://tex.z-dn.net/?f=Rate%3Dk%5BA%5D%5E1)
k= rate constant
![0.00250=k[0.484]^1](https://tex.z-dn.net/?f=0.00250%3Dk%5B0.484%5D%5E1)
The rate constant, k, for this reaction is
b) Expression for rate law for first order kinetics is given by:
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
Thus does not depend on concentration.
