What the question for this assessment
Answer:
θ = 28.9
Explanation:
For this exercise let's use the law of refraction
n₁ sin θ₁ = n₂ sin θ₂
where we use index 1 for air and index 2 for water where the fish is
sin θ₂ = n₁ / n₂ sin θ₁
in this case the air repair index is 1 and the water 1.33
we substitute
sin θ₂ = 1 / 1.33 sin t 40
sin θ = 0.4833
θ = sin⁻¹ 0.4833
θ = 28.9
Explanation:
It is known that octane is a hydrocarbon and London dispersion forces are the main intermolecular forces which are present in it.
Whereas water molecules tend to form hydrogen bonding forces which are actually much stronger than dipole-dipole interactions. This means that more energy is necessary to separate water molecules from one another than to separate octane molecules from one another.
Hence, we can conclude that surface tension of octane is expected to be lower than that of water when the two are considered at the same temperature.
