Answer:16.096
Explanation:
Given
mass of dog
mass of boat
distance moved by dog relative to ground=
distance moved by boat relative to ground=
Distance moved by dog relative to boat=7.8m
There no net force on the system therefore centre of mass of system remains at its position
0=
0=
i.e. boat will move opposite to the direction of dog
Now
substitutingvalue
now the dog is 22.5-6.403=16.096m from shore
Let's assume that the pressure given is 771 torr.
Answer:
747.44 torr
Explanation:
The eudiometer tube is a setup that collects gas in a liquid (generally water). After the thermal equilibrium, the gas becomes in equilibrium with the vapor of water above the liquid.
By Dalton's law, the total pressure of a mixture is the sum of the partial pressure of its components. The partial pressure is the pressure that the gas would have at the same conditions if it was alone. So, the pressure of the dry gas is its partial pressure.
The total pressure is the barometric pressure, and the partial pressure of the water vapor at 20°C is 23.56 torr (the value can be found at a thermodynamic table). So, the pressure of the dry gas (P) is:
771 = 23.56 + P
P = 771 - 23.56
P = 747.44 torr
Answer:
The velocity of the wave is, v = 180,000 m/s
Explanation:
Given data,
The frequency of the wave, f = 900 Hz
The wavelength of the wave, λ = 200 m
The formula for the speed of the wave when the frequency and wavelength are known,
v = λ x f
Substituting the given values in the above equation,
v = 200 m x 900 Hz
v = 180000 m/s
Hence, the velocity of the wave is, v = 180,000 m/s
Answer:
y = 428.67 m and x all = 1513.68 m
Explanation:
This problem of kinematics can be divided into two parts: a first part when the rockets work a second as a parabolic launch.
Let's do the first part, let's calculate the speed just when the engines turn off
vf = v₀ + at
vf = 78 + at
vf = 78 +12 3
vf = 114 m / s
This is the speed with which the second part begins vo = 114 m / s with an Angle of 38º
Also at this time a distance is displaced, we calculate the distance traveled (in the direction of the acceleration)
d = v₀ t + ½ a t²
d = 78 3 + ½ 12 3²
d = 288 m
Let's use trigonometry to find the components
x₀ = d cos 38 = 288 cos 38
y₀ = d sin38 = 288 sin38
x₀ = 226.95 m
y₀ = 177.31 m
Second part
Let's calculate the maximum height, at this point its vertical speed is zero (vfy = 0)
Let's decompose the initial velocity using trigonometry
vₓ = v₀ cos 38
= v₀ sin38
vₓ = 114 cos 38
= 114 sin38
vₓ = 89.83 m / s
= 70.19 m / s
² = ² - 2g (y -y₀)
0 = ² -2g (y -yo)
y-y₀ = ² / 2g
y-y₀ = 70.19²/2 9.8
y = 251.36 + y₀
y = 251.36 + 177.31
y = 428.67 m
This is the maximum height from the point where the movement began, that is, the ground.
Now let's calculate the range
R = vo² sin 2θ / g
R = 114² sin 2 38 /9.8
R = 1286.73 m
This is the scope of the parabolic movement, we must add the horizontal distance traveled in the first part
x all = R + xo
x all = 1286.73 + 226.95
x all = 1513.68 m