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Ganezh [65]
3 years ago
6

What do you think of my lab report so far?

Chemistry
2 answers:
8090 [49]3 years ago
5 0
Fix ur transition, it sounds choppy

bekas [8.4K]3 years ago
5 0
I can only see one page. If you are doing this under Perdue Owl structure, then you will need a cover page as well as numbers on the page and a reference page at the end. Some professors also want a content page
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the reaction of aluminum with chlorine gas is shown 2Al + 3Cl2 -> 2AlCl3 based on this equation how many molecules of chlorin
Vanyuwa [196]

45 molecules of chlorine gas (Cl₂) are needed to react with 30 atoms of aluminum (Al)

The balanced equation for the reaction is given below:

2Al + 3Cl₂ —> 2AlCl₃

From the balanced equation above,

2 atoms of Al required 3 molecules of Cl₂.

With the above information, we can determine the number of molecules of Cl₂ needed to react with 30 atoms of Al. This can be obtained as follow:

From the balanced equation above,

2 atoms of Al required 3 molecules of Cl₂.

Therefore,

30 atoms of Al will require = \frac{30 * 3}{2}\\ = 45 molecules of Cl₂.

Thus, 45 molecules of chlorine gas (Cl₂) are needed to react with 30 atoms of aluminum (Al)

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Answer:

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Explanation:

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