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2 years ago

A light bulb whose resistance is 240 ohms is connected to a 120 voltage source. What is the current through the bulb?

Physics

1 answer:

Sedaia [141]2 years ago

7 0

Answer:

0.5A

Explanation:

Using $R = \frac{V}{I}$ ,

R is the resistance (in Ohms)

V is the voltage (in V)

I is the current (in A)

$240=\frac{120}{I}$

I = 0.5A

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alexandr1967 [171]

Answer:

54.6°

Explanation:

From law of reflection i=r.

So, construct the reflected ray at 55.7°degrees from the normal and let it fall on the other mirror.

Now draw the second normal at the point of incidence and again measure the angle of incidence, and draw the angle of reflection.

If you consider triangle AOB, one angle is ∠AOB=90°

and ∠OAB is 54.6°

From angle sum property third angle ie ∠ABO=180°-90°-54.6°=35.4°

So, the second incident angle will be 54.6°

Hence, the second reflected angle will be 54.6 degrees.

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3 years ago

How can you be both at rest and also moving at 100,000 km/h at the same time

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3 years ago

Which statement about gravity is true?

SVETLANKA909090 [29]

Out of the given options, ‘it is described as a fundamental force and therefore does not depend on other forces’ is the true statement about gravity.

Answer: Option B

<u>Explanation: </u>

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$F=G \times \frac{m_{1} m_{2}}{r^{2}}$

Where,

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3 years ago

The graph above shows the position and time calculate the velocity of the particle from T=0s to T=4s?

zzz [600]

Answer:

The velocity of the particle from T = 0 s to T = 4 s is;

0.5 m/s

Explanation:

The given parameters from the graph are;

The initial displacement (covered) at time, t₁ = 0 s is x₁ = 1 m

The displacement covered at time, t₂ = 4 s is x₂ = 3 m

The graph of distance to time, from time t = 0 to time t = 4 is a straight line graph, with the velocity given by the rate of change of the displacement to the time which is dx/dt which is also the slope of the graph given as follows;

$The \ slope \ of \ the \ displacement \ time \ graph, \ m =velocity, \ v= \dfrac{x_2 - x_1}{t_2 - t_1}$