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svetoff [14.1K]
3 years ago
15

4. In the Exploration, the sled does not move at all when two equal forces are applied

Physics
1 answer:
Assoli18 [71]3 years ago
7 0

Answer:

The net force is zero, so the acceleration is zero

Explanation:

Newton's second law states that the acceleration of an object is proportional to the net force applied to it, according to the equation:

\sum F = ma (1)

where

\sum F is the net force on the object

m is the mass of the object

a is its acceleration

In this problem, we have a sled acted upon two forces, F_1, F_2. So the net force on the sled is

\sum F = F_1 + F_2 (2)

however, we are told that the two forces are equal in magnitude but in opposite directions, so

F_1 = F\\F_2 = -F

So, eq.(2) becomes

\sum F = F+(-F) = 0

and so eq.(1) becomes

\sum F = ma = 0

which means

a=0

so the acceleration of the sled is zero, and if the sled was at rest, it will not move.

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Un cubo de madera de densidad 0.780 g/cm³ mide 11.2 cm en un lado. Cuando se coloca en agua, ¿qué altura del bloque flotará sobr
Stolb23 [73]

Answer:

2.464 cm above the water surface

Explanation:

Recall that for the cube to float, means that the volume of water displaced weights the same as the weight of the block.

We calculate the weight of the block multiplying its density (0.78 gr/cm^3) times its volume (11.2^3  cm^3):

weight of the block = 0.78 * 11.2^3  gr

Now the displaced water will have a volume equal to the base of the cube (11.2 cm^2) times the part of the cube (x) that is under water. Recall as well that the density of water is 1 gr/cm^3.

So the weight of the volume of water displaced is:

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we make both weight expressions equal each other for the floating requirement:

0.78 * 11.2^3 = 11.2^2 * x

then x = 0.78 * 11.2 cm = 8.736 cm

This "x" is the portion of the cube under water. Then to estimate what is left of the cube above water, we subtract it from the cube's height (11.2 cm) as follows:

11.2 cm - 8.736 cm = 2.464 cm

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It takes 15 min to drive 6.0 mi in a straight line to the local hospital. It takes 10 min to go the last 3.0 mi, 2.0 min to go t
Gala2k [10]

Answer:

36.87 km/h

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Convert all the units in SI system

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d2 = 3 mi = 4828.02 m

t2 = 10 min = 10 x 60 = 600 s

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d4 = 0.5 mi = 804.67 m

t4 = 0.5 min = 0.5 x 60 = 30 s

Total distance, d = d1 + d2 + d3 + d4

d = 9656.04 + 4828.02 +  1609.34 + 804.67 = 16898.07 m = 16.898 km

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The ratio of the total distance covered to the total time taken is called average speed.

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6 0
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The statement that can be used to answer this  question is:

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8 0
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max2010maxim [7]

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But if they are not in equilibrium.

U will find the difference in the two torque

find the attached file for solution

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2 years ago
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