All categories

3 years ago

Consider the following balanced chemical equation representing the combustion of propane gas:

Chemistry

1 answer:

lora16 [44]3 years ago

6 0

Answer:

We are given the following equation:

C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g)

we can see that the number of moles of H2O is 4/3 time the moles of CO2

So, the easiest way to find the number of moles of H2O is to find the number of moles of CO2 and multiply it by 4 / 3

Moles of CO2:

Molar mass of CO2 = 44 grams / mol

Moles of CO2 = Given mass / Molar mass

Moles of CO2 = 16.3 / 44 moles

Moles of H2O:

Moles of H2O = Moles of CO2 * 4 / 3

Moles of H2O = 16.3 * 4 / 3 * 44

Moles of H2O = 16.3 / 3 * 11

Moles of H2O = 16.3 / 33

Moles of H2O = 0.5 moles (approx)

Therefore, along with 16.3 grams of CO2, 0.5 moles of H2O will also be formed

You might be interested in

Determine the molality of a solution in which 2.5 grams of glucose C12H22011 are dissolved in 1492grams of water.

Roman55 [17]

The answer is A hope that helps

6 0

3 years ago

A barium hydroxide solution is prepared by dissolving 2.06 g of Ba(OH)2 in water to make 32.9 mL of solution. What is the concen

navik [9.2K]

Answer: 1.36 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n = moles of solute

To calculate the moles, we use the equation:

moles of solute= $\frac{\text {given mass}}{\text {molar mass}}=\frac{2.06g}{171g/mol}=0.0120moles$

$Molarity=\frac{0.0120\times 1000}{32.9}=0.364M$

The balanced reaction between barium hydroxide and perchloric acid:

$2HCIO_4+Ba(OH_)2\rightarrow BaCIO_4+2H_2O$

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HClO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ba(OH)_2$

We are given:

$n_1=1\\M_1=?\\V_1=8.50mL\\n_2=2\\M_2=0.364M\\V_2=15.9mL$

Putting values in above equation, we get:

$1\times M_1\times 8.50=2\times 0.364\times 15.9\\\\M_1=1.36M$

Thus the concentration of the acid is 1.36 M

4 0

3 years ago

A gas sample has a temperature of 19 °C with an unknown volume. The

andreev551 [17]

Answer: 373 mL

Explanation:

Since there is no change in pressure, the formula: V / T = V / T can be used.

However, you must first convert the temperatures to Kelvin by adding 273 to them:

(19 + 273) = 292K and (90 + 273) = 363K.

Now, plug in: V / 292 = 464 / 363 → V = 373 mL :)

4 0

3 years ago

In a very violent reaction called a thermite reaction, aluminum metal reacts with iron (III) oxide to form iron metal and alumin

leva [86]

Here's the equation:
Fe2 O3 + 2Al → 2Fe + Al2 O3

Here's the question.
What mass of Al will react with 150g of Fe2 O3?

In every 2 moles Al you need 1 mole Fe2O3 

moles = mass / molar mass 
moles Fe2O3 = 150 g / 159.69 g/mol 
= 0.9393 moles 

moles Al needed = 2 x moles Fe2O3 
= 2 x 0.9393 mol 
= 1.879 moles Al needed 

mass = molar mass x moles 
mass Al = 26.98 g/mol x 1.879 mol 
= 50.69 g 
= 51 g (2 sig figs)

So the mass of Al that will react with 150g of Fe2 O3 is 51 grams.

3 0

4 years ago

Someone please help me !!

Bezzdna [24]

Answer:

Explanation:

6 0

3 years ago