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lions [1.4K]
3 years ago
7

A baboon pushes a 3.1 kg stone with 150 j of kinetic energy. What is the stone’s speed?

Physics
1 answer:
azamat3 years ago
4 0

The speed of the stone is 9.8 m/s

<u>Explanation:</u>

Given data,

Mass - 3 kg    K.E 150-J

We have to find the speed of the stone

We have the formula

K.E =1/2 m× v ²

Rewrite the equation as

v= √ 2×K.E/m

v= √2 ×150/ 3.1

v=9.83 m/s

The speed of the stone is 9.8 m/s

<u />

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Answer:

0.053 rad/s^2

Explanation:

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A 5.00 kg rock whose density is 4300 kg/m3 is suspended by a string such that half of the rock's volume is under water. You may
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Answer:

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Explanation:

From the question we are told that

    The mass of the rock is m_r = 5.00 \ kg =  5000 \ g

       The density of the rock is \rho  =  4300 \ kg/m^3 =  4.3 g/dm^3

       

Generally the volume of the rock is mathematically evaluated as

          V    =  \frac{m_r}{\rho}

substituting values

        V    =  \frac{5000}{4.3}

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The volume of the rock immersed in water is

      V_w = \frac{V}{2}  

substituting values

     V_w = \frac{1162.7 }{2}

     V_w = 581.4 \ dm^3

mass of water been displaced by the this volume is

     m_w  = V_w     According to Archimedes principle

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     m_w =  0.5814 \ kg

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The actual weight of the rock is  

      W_r  =  m_r * g

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The tension on the string is

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substituting values

       T  = 49.0 -  5.698

       T  =  43.302 \ N

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