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irina1246 [14]
3 years ago
9

The diagram below shows part of the rock cycle.

Chemistry
2 answers:
snow_lady [41]3 years ago
5 0
The answer is igneous
Alika [10]3 years ago
5 0
I think the answer is igneous rocks.<span />
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When a catalyst is added to a reversible reaction in equilibrium state the value of equilibrium constant
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Explanation:

The value of equilibrium constant doesn't change when a catalyst is added.

Equilibrium constant depends on Concentration of reactants , Pressure and Temperature.

6 0
3 years ago
Suppose a large atom bonds with a small
Zielflug [23.3K]
A large atom means that the radius would be large, meaning that the effective nuclear charge is low, therefore a lower electronegativity based on the periodic table. A smaller atom would mean the opposite, therefore a higher electronegativity. This combination would mean that the new molecule is polar.

Also, to answer your question, it would be most likely different from both atoms, as size doesn't really matter in a compound's properties.
3 0
3 years ago
The overall charge of an atom is ________ if the number of electrons is ________ than the number of protons.
miss Akunina [59]
The overall charge of an atom is positive if the number of electrons is less than the number of protons. Electrons are negatively charged particles while protons are positively charged particles. If there are less electrons as compared to the number of protons in an atom, then naturally the overall charge of the atom would be positive since there are excess protons. Another case would be that the overall charge of an atom is negative if the number of electrons is greater than the number of protons. An atom having more electrons than the number of the protons present would lead to a negative value of the charge since there are excess electrons.
8 0
3 years ago
Calculate the mass of hydrogen in 500 g of Al(C2H3O2)3
Zigmanuir [339]
<span>Answer is: the mass of hydrogen is 22,05 grams.
m(</span>Al(C₂H₃O₂)₃)<span> = 500 g.
M</span>(Al(C₂H₃O₂)₃) = 27 + 6 ·12 + 9 · 1 + 6 · 16 · g/mol = 204 g/mol.<span>
n</span>(Al(C₂H₃O₂)₃) = m(Al(C₂H₃O₂)₃) ÷ M(Al(C₂H₃O₂)₃).
n(Al(C₂H₃O₂)₃) = 500 g ÷ 204 g/mol.
n(Al(C₂H₃O₂)₃) = 2,45 mol.
n(Al(C₂H₃O₂)₃) : n(H) = 1 : 9.
n(H) = 22,05 mol.
m(H) = 22,05 mol · 1 g/mol
m(H) = 22,05 g.

3 0
3 years ago
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